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katrin2010 [14]
2 years ago
6

Consider the chemical equation. 2NBr3 + 3NaOH Right arrow. N2 + 3NaBr + 3HOBr If there are 40 mol of NBr3 and 48 mol of NaOH, wh

at is the excess reactant?
Chemistry
1 answer:
Maslowich2 years ago
4 0

Answer:

NBr₃ is the excess reactant.

Explanation:

  • 2NBr₃ + 3NaOH → N₂ + 3NaBr + 3HOBr

We can solve this problem by <u>calculating how many moles of NaOH would react completely with 40 moles of NBr₃</u>, using the <em>stoichiometric coefficients </em>of the reaction:

  • 40 mol NBr₃ * \frac{3molNaOH}{2molNBr_3} =60 moles NaOH

As the required number of NaOH moles is higher than the available number (60 required vs 48 available), NaOH is the limiting reactant.

As such, the excess reactant is NBr₃.

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_____Mg + ____Fe2O3 → _____Fe + ____MgO
german

Answer:

3Mg + Fe₂O₃  → 2 Fe + 3MgO

Explanation:

Chemical equation;

Mg + Fe₂O₃  →  Fe + MgO

Balanced Chemical equation;

3Mg + Fe₂O₃  → 2Fe + 3MgO

This is the balanced equation. There are three magnesium, two iron and three oxygen atoms are on both side of equation thus it follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

7 0
3 years ago
How do cells use lipids and carbohydrates?
Nata [24]

Answer:

Animals tend to use carbohydrates primarily for short-term energy storage, while lipids are used more for long-term energy storage. Carbohydrates are stored as glycogen in animals while lipids are stored as fats (in plants carbohydrates are stored as cellulose and lipids as oils)

Explanation:

hope this helps!

8 0
3 years ago
Read 2 more answers
scandium47 has a half-life of 35s. suppose you have a 45g sample of scadium 47 how much of the sample remains unchanged after 14
Mars2501 [29]

 The much  of the sample that would remain  unchanged  after 140 seconds is 2.813 g

Explanation

Half life  is time taken for the quantity  to reduce  to half its original value.

if the half life  for Scandium  is 35 sec, then the number  of half life in 140 seconds

=140 sec/ 35 s = 4 half life

Therefore 45 g after first half life = 45 x1/2 =22.5 g

               22.5 g after second half life = 22.5 x 1/2 =11.25 g

            11.25 g after third half life = 11.25 x 1/2 = 5.625 g

             5.625 after  fourth half life = 5.625 x 1/2 = 2.813

therefore 2.813 g  of Scandium 47 remains  unchanged.

4 0
3 years ago
MgNH4PO4•6H2O loses H2O in a stepwise fashion as it is heated. Between 40 degrees celsius and 60 degrees celsius, the monohydrat
tino4ka555 [31]

Answer:

\%\ Composition\ of\ phosphorus=20.00\ \%

Explanation:

The molecular formula of the monohydrate formed = MgNH_4PO_4.H_2O

The molecular mass of the monohydrate formed = Mass_{Mg}+Mass_{N}+6\times Mass_{H}+5\times Mass_O

So, Mass = 24 + 14 + 6 × 1 + 5 × 16 = 155 g

Mass of phosphorus = 31 g

Thus,

\%\ Composition\ of\ phosphorus =\frac{Mass_{phosphorus}}{Total\ mass}\times 100

\%\ Composition\ of\ phosphorus=\frac{31}{155}\times 100

\%\ Composition\ of\ phosphorus=20.00\ \%

4 0
3 years ago
How many seconds does it take a race horse to run six furlongs at 40.7 miles per hour if: I furlong = 40 rods; 5.5 yards = 1 rod
lana [24]

Distance traveled by the race horse=6 furlongs

Converting the distance from furlongs to rods: 40 rods =1 furlong

6 furlongs*\frac{40rods}{1furlong} =240rods

Converting the distance from rods to yards, feet and miles: 5.5 yards = 1 rod, 3foot =1 yard, 1 mile = 5280 feet.

240rods*\frac{5.5yards}{1rod}*\frac{3foot}{1yard}*\frac{1mi}{5280feet}=0.75mi

The given speed of race horse = 40.7mi/hr

Calculating the time required:

0.75mi*\frac{1hr}{40.7mi}*\frac{60min}{1hr}*\frac{60s}{1min}= 66.34s

Therefore, 66.34 s is required for a race horse to run six furlongs at 40.7 miles per hour.

8 0
3 years ago
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