The rate law for the reaction : r=k.[A]²
<h3>Further explanation</h3>
Given
Reaction
A ⟶ B + C
Required
The rate law
Solution
The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants
For the second-order reaction it can be:
1. the square of the concentration of one reactant.
![\tt r=k[A]^2](https://tex.z-dn.net/?f=%5Ctt%20r%3Dk%5BA%5D%5E2)
2. the product of the concentrations of two reactants.
![\tt r=k[A][B]](https://tex.z-dn.net/?f=%5Ctt%20r%3Dk%5BA%5D%5BB%5D)
And the reaction should be(for second order) :
2A ⟶ B + C
Thus, for reaction above (reactant consumption rate) :
![\tt r=-\dfrac{\Delta A}{2\Delta t}=k[A]^2](https://tex.z-dn.net/?f=%5Ctt%20r%3D-%5Cdfrac%7B%5CDelta%20A%7D%7B2%5CDelta%20t%7D%3Dk%5BA%5D%5E2)
Answer: 0.745 g of 
will be produced from 1.08 g of sodium sulfate
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and 
is the excess reagent.
According to stoichiometry :
3 moles of produce = 3 moles of
Thus 0.0076 moles of will require=
of
Mass of 
Thus 0.745 g of will be produced from 1.08 g of sodium sulfate
94.6 g. You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.
We can use a version of the <em>dilution formula</em>
<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2
where
<em>m</em> represents the mass and
<em>C</em> represents the percent concentrations
We can rearrange the formula to get
<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)
<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %
<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %
∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g
Sugar. It is solid and its atoms have less kinetic energy to overcome the bonding force. So, the bonding force is stronger than water, which is liquid and has more kinetic energy to overcome the bonding force of atoms. So, water has less strong force of attraction. Hence, sugar has stronger forces of attraction.
Answer:
The answer is Frost Point.
Explanation:
The temperature to which the air must be cooled, with constant pressure, to reach saturation (in relation to liquid water), is called the dew point. The dew point gives a measure of the water vapor content in the air. The higher, the greater the concentration of water vapor in the air. However, when cooling produces saturation at a temperature of 0 ° C or less, the temperature is called a frost point. The water vapor is deposited as frost on a surface whose temperature is below the dew point.
