Consider the chemical equation. 2NBr3 + 3NaOH Right arrow. N2 + 3NaBr + 3HOBr If there are 40 mol of NBr3 and 48 mol of NaOH, wh
1 answer:
Answer:
NBr₃ is the excess reactant.
Explanation:
- 2NBr₃ + 3NaOH → N₂ + 3NaBr + 3HOBr
We can solve this problem by <u>calculating how many moles of NaOH would react completely with 40 moles of NBr₃</u>, using the <em>stoichiometric coefficients </em>of the reaction:
- 40 mol NBr₃ *
=60 moles NaOH
As the required number of NaOH moles is higher than the available number (60 required vs 48 available), NaOH is the limiting reactant.
As such, the excess reactant is NBr₃.
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The answer for the following question is answered below.
- <em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>
Explanation:
Given:
Initial pressure of the gas = 1.34 atm
Initial temperature of the gas = 273 K
final temperature of the gas = 312 K
To solve:
Final temperature of the gas
We know;
From the ideal gas equation
P × V = n × R × T
So;
from the above equation we can say that
<em>P ∝ T</em>
= constant
=
Where;
= initial pressure of a gas
= final pressure of a gas
= initial temperature of a gas
= final temperature of a gas
=
= 1.76 atm
<em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>