The answer is decomposition
Examples: phosphorus trichloride
( PCl3)
Phosphorus trioxide
( P2O3)
Answer:
301.8 g
Explanation:
We prepare a solution with 200.4 g of water (solvent) and 101.42 g of salt (solute). The mass of the solution is equal to the sum of the mass of the solvent and the mass of the solute.
m(solution) = m(solute) + m(solvent)
m(solution) = 200.4 g + 101.42 g
m(solution) = 301.8 g (we round-off to one decimal according to the significant figures rules)
Both molecules are long chain based polymers of carbohydrates. This can easily be told based on the fact that the 3 main elements that make up a sugar are present C , H and O.
This would be C11H12O11 in terms of simple empirical formula.
The reaction of Na2CrO4 (aq) and AgNO3 (aq) is as follows:
2AgNO3 (aq) +Na2CrO4 (aq) ⇒Ag2CrO4 (s) + 2NaNO3 (aq).
During this reaction, part of the CrO42- reacts with Ag+ and precipitates out of the solution, part of the CrO42- (excess amount) remains in the solution.
To find out how much CrO42- is reacted:
Moles of initial CrO42- = 0.075 L * 2.5 M = 0.1875 mole
Moles of initial Ag+ = 0.125 L * 1.79 M = 0.2238 mole
The reaction ratio between CrO42- and Ag+ is 1:2 according to the equation. So moles of CrO42- that is reacted is 0.2238 mole/2 = 0.1119 mole. Therefore, moles of CrO42- that remains in the solution is 0.1875mole-0.1119mole = 0.0756 mole
So the final concentration of CrO42- in the solution is 0.0756mole/(0.075L+0.125L)= 0.378 M.