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UNO [17]
3 years ago
11

What is meant in astronomy by the phrase "adaptive optics?

Physics
1 answer:
Sergeu [11.5K]3 years ago
7 0
<h2>Answer: a.The mirrors and eyepiece of a large telescope are spring-loaded to allow them to return quickly to a known position. </h2>

Explanation:

Adaptive optics is a method used in several astronomical observatories to counteract in real time the effects of the Earth's atmosphere on the formation of astronomical images.

This is done through the insertion into the optical path of the telescope of sophisticated deformable mirrors supported by a set of computationally controlled actuators. Thus obtaining clear images despite the effects of atmospheric turbulence that cause the unwanted distortion.

It should be noted that with this technique it is also necessary to have a moderately bright reference star that is very close to the object to be observed and studied. However, it is not always possible to find such stars, so a powerful laser beam is used to point towards the Earth's upper atmosphere and create artificial stars.

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You drive a car 640 m to the east, then 340 m to the north what is the magnitude of your displacement
mixer [17]

Magnitude of displacement = \sqrt{640^2 + 340^2}

Adding the squares gives displacement = \sqrt{525,200}

Displacement =  \sqrt{525,200} ≈ 724.7m

6 0
3 years ago
[ b) The time of reverberation of an empty hall without and with 500 audiences is 1.5 sec and 1.4 sec respectively. Find the rev
Lilit [14]

The reverberation time with 800 audiences is 0.875 seconds.

<h3>Reverberation time with 800 audience</h3>

R₁V₁ = R₂V₂

where;

  • R₁ is the reverberation time with 400 audience
  • R₂ is the reverberation time with 800 audience
  • V₁ is initial volume
  • V₂ is final volume

R₂ = R₁V₁/V₂

R₂ = (1.4 x 500) / 800

R₂ = 0.875 seconds

Thus, the reverberation time with 800 audiences is 0.875 seconds.

Learn more about reverberation time here: brainly.com/question/9278479

#SPJ1

4 0
2 years ago
Pluto was first discovered in 1930.It was determined to be located about 39.48 times as far away from the Sun as Earth is. How l
Mice21 [21]

Answer:

It takes total 248 years for Pluto to orbit the sun.

7 0
3 years ago
ASAP please!! <br>The force vectors on an aircraft are as shown. Find the net (resultant force).
ioda

Answer:

The magnitude of the net force is 5430N

Explanation:

I suggest to define the axes as aligned to the axis of the plane. This will require you to decompose only one vector, namely the Weight. We need two components of the W force: one in horizontal direction of the plane, the other perpendicular to it. Through a simple triangle argument you will se that the plane-horizontal component of W is

W_D=3600 N\cdot\sin 27^\circ=1634N

acting in the direction of the Drag, and the plane-perpendicular component is:

W_L=-3600N\cdot\cos 27^\circ=-3208N

with negative sign since it counteracts the Lift.

So the components of the netforce F are:

F_h=T-D-W_D=(8000-1000-1634)N=5366N\\F_v=L+W_L=(4100-3208)N=829N

The magnitude of the  net force is:

|F|=\sqrt{5366^2+829^2}N = 5430N


6 0
3 years ago
Compute the ratio of the rate of heat loss through a single-pane window with area 0.15 m2 to that for a double-pane window with
Rudik [331]

Answer:

2.80321285141

Explanation:

L_g = Thickness of glass = 4.5 mm

k_g = Thermal conductivity of glass = 0.8 W/mK

R_0 = Combined thermal resistance = 0.15\times m^2K/W

L_a = Thickness of air = 6.6 mm

k_a = Thermal conductivity of air = 0.024 W/mK

The required ratio is the inverse of total thermal resistance

\dfrac{2(L_g/k_g)+R_0+(L_a/k_a)}{(L_g/k_g)+R_0}\\ =\dfrac{2(4.5\times 10^{-3}/0.8)+0.15+(6.6\times 10^{-3}/0.024)}{(4.5\times 10^{-3}/0.8)+0.15}\\ =2.80321285141

The ratio is 2.80321285141

4 0
3 years ago
Read 2 more answers
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