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3 years ago

What is meant in astronomy by the phrase "adaptive optics?

1 answer:

7 0

<h2>Answer: a.The mirrors and eyepiece of a large telescope are spring-loaded to allow them to return quickly to a known position. </h2>

Explanation:

Adaptive optics is a method used in several astronomical observatories to counteract in real time the effects of the Earth's atmosphere on the formation of astronomical images.

This is done through the insertion into the optical path of the telescope of sophisticated deformable mirrors supported by a set of computationally controlled actuators. Thus obtaining clear images despite the effects of atmospheric turbulence that cause the unwanted distortion.

It should be noted that with this technique it is also necessary to have a moderately bright reference star that is very close to the object to be observed and studied. However, it is not always possible to find such stars, so a powerful laser beam is used to point towards the Earth's upper atmosphere and create artificial stars.

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Which statement best compares the momentum of a 5-kilogram fish swimming at a speed of 10 meters/second and a 2-kilogram fish sw

ruslelena [56]

M = mass of the larger fish =5kg
V = velocity of the larger fish =10m/s
m = mass of the smaller fish =2kg
v = velocity of the smaller fish =10m/s
formula=
MV = mv
5kg*10m/s=2kg*10m/s
biggern mass fish has more momentum
hope this helps

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3 years ago

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A car is designed to last an average of 12 years with a standard deviation of 0.8 years. What is the probability that a car will

weeeeeb [17]

-2,5SD = 2.1%
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3 years ago

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Suppose the original segment of wire is stretched to 10 times its original length. How much charge must be added to the wire to

Debora [2.8K]

Here we want to study how the linear charge density changes as we change the measures of our body.

We will find that we need to add 9*Q of charge to keep the linear charge density unchanged.

I will take two assumptions:

The charge is homogeneous, so the density is constant all along the wire.

As we work with a linear charge density we work in one dimension, so the wire "has no radius"

Originally, the wire has a charge Q and a length L.

The linear charge density will be given by:

λ = Q/L

Now the length of the wire is stretched to 10 times the original length, so we have:

L' = 10*L

We want to find the value of Q' such that λ' (the linear density of the stretched wire) is still equal to λ.

Then we will have:

λ' = Q'/L' = Q'/(10*L) = λ = Q/L

Q'/(10*L) = Q/L

Q'/10 = Q

Q' = 10*Q

So the new charge must be 10 times the original charge, this means that we need to add 9*Q of charge to keep the linear charge density unchanged.

If you want to learn more, you can read:

brainly.com/question/14514975

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3 years ago

Explain how you can determine the direction of a magnetic field produced by a wire if you know the diection of the current throu

ololo11 [35]

Explanation:

Right hand thumb rule : Point the thumb of your right hand in the direction of the current flow, the direction of curvature of the fingers will give us the direction of the magnetic field produced by current carrying wire. This rule was given by Maxwell.

1) If the current is moving in upward direction , the direction of the magnetic field will be in anti clock wise direction.

2) If the current is moving in downward direction , the direction of the magnetic field will be in clock wise direction.

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3 years ago

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How far away is a cliff if an echo is heard 0.486 s after the original sound? Assume that sound traveled at 343 m/s on that day.

goldfiish [28.3K]

143m/s if you just perhaps by what you know you'll figure it out

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3 years ago