I'm pretty sure it's D. The stars don't influence the moon's phases.
Ideal Gas Law PV = nRT
THE GASEOUS STATE
Pressure atm
Volume liters
n moles
R L atm mol^-1 K^-1
Temperature Kelvin
pv = rt
divide both sides by v
pv/v = rt/v
p = rt/v
answer: p = rt/v
Ideal Gas Law: Density
PV = NRT
PV = mass/(mw)RT
mass/V = P (MW)/RT = density
Molar Mass:
Ideal Gas Law PV = NRT
PV = mass/(MW) RT
MW = mass * RT/PV
Measures of Gases:
Daltons Law of Partial Pressures; is the total pressure of a mixture of gases equals the sum of the partial pressures of the individual gases.
Total = P_ A + P_ B
P_ A V = n_ A RT
P_ B V = n_ B R T
Partial Pressures in Gas Mixtures:
P_ total = P_ A + P_ B
P_ A = n_ A RT/V P_ B = n_ B RTV
P_ total = P_ A + P_ B = n_ total RT/V
For Ideal Gasses:
P_ A = n_ A RT/V P_ total = n_ toatal RT/V
P_ A/P_ total = n_ A RTV/n_ total RTV
= n_ A/n_ total = X_ A
Therefore, P_ A = X_ A P_ total.
PV = nRT
P pressure
V volume
n Number of moles
R Gas Constant
T temperture (Kelvin.).
Hope that helps!!!!!! Have a great day : )
Answer:
When two objects collide and stick together, what will happen to their speed, assuming momentum is conserved? They will move at the same velocity as whichever object was fastest initially. They will move at the same velocity of whichever object was slowest initially.
Explanation:
Answer:
Current in the hair dryer will be equal to 15 A
Explanation:
We have given that household is operated at 110 volt
So potential difference V =110 volt
Power drawn by hairdryer is P = 1650 watt
We have to find the current in the hair dryer
We know that power is given as P = VI, here V is potential difference and I is current
So 
I = 15 A
So current in the hair dryer will be equal to 15 A
Answer:
-0.1875 V.
Explanation:
Using
E₂ = MdI₁/dt........................ Equation 1
Where E₂ = Voltage induced in the second coil, M = mutual inductance of both coil, dI₁ = change in current in the first coil, dt = change in time.
Given: M = 3.00 mH = 0.003 H, dI₁ = (0-2.50) = -2.5 A, dt = 40 ms = 0.04 s.
Substitute into equation 1
E₂ = 0.003(-2.5)/0.04
E₂ = -0.1875 V.
Hence the induced emf = -0.1875 V.
