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Tanzania [10]
3 years ago
13

Light refracts due to a change in ________

Physics
1 answer:
Nonamiya [84]3 years ago
7 0

The answer is b) Speed.

Light refracting is the just the change of direction of the light. And the change of direction in the light is caused by the change in speed.

An example of this would be when light travels into the water. When light hits the water it slows down, causing a change in speed and ultimately changing the direction, causing a light refraction to occur.

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A battery charger is connected to a dead battery and delivers a current of 3.5 a for 4 hours, keeping the voltage across the bat
oksano4ka [1.4K]
The power delivered is equal to the product between the voltage V and the current I:
P=VI=(16 V)(3.5 A)=56 W

This power is delivered for a total time of t=4h=4 \cdot 3600 s = 14400 s, so the total energy delivered to the battery is
E=Pt = (56 W)(14400 s)=806400 J=806.4 kJ
5 0
3 years ago
Susan gently pushes the tip of her finger against the eraser on her pencil and the pencil does not move. Which of the
pochemuha

Answer: D. ➡️⬅️

Explanation: I just knew the answer ;)

6 0
3 years ago
A proton travels with a speed of 5.02×10⁶ m/s in a direction that makes an angle of 60.0° with the direction of a magnetic ficld
Triss [41]

The magnitude of the magnetic force on the proton is 1.25× 10—¹³ N.

Speed of the proton = 5.02 × 10 ⁶ m /a

Angel of between the velocity and the magnetic force = 60 °

The magnitude of magnetic field B = 0.180 T

The magnitude of the magnetic force on the proton is,

F = q(v \times B)

F = qvB \: sin \:  θ

F = 1.6 \times 10 ^{ - 19}  \times 5.02 \times 10 ^{6}  \times 0.180 \times  \: sin \: 60°

= 1.25 \times 10 ^{ - 13}  \: N

Therefore, the magnitude of the magnetic force on the proton is 1.25× 10—¹³ N.

To know more about magnetic force, refer to the below link:

brainly.com/question/23096032

#SPJ4

4 0
1 year ago
Need amswer fast plz
FrozenT [24]

Answer:

I need this for may schooling

6 0
2 years ago
Use Eq. cosϕ=R/Z to show that the average power delivered by the source in an L−R−C series circuit is given by Pav = I^2rmsR .
Evgen [1.6K]

Answer:

Explanation:

In a L C R circuit, the average power is given by

P_{av}=V_{rms}I_{rms}Cos\phi

As given in the question

CosФ = R / Z

And we know that

V_{rms}=I_{rms}\times Z

So

P_{av}=I_{rms}\times Z\times I_{rms}\times \frac{R}{Z}

P_{av}=I_{rms}^{2}\times R

6 0
3 years ago
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