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2 years ago

Light refracts due to a change in ________

Physics

1 answer:

Nonamiya [84]2 years ago

7 0

The answer is b) Speed.

Light refracting is the just the change of direction of the light. And the change of direction in the light is caused by the change in speed.

An example of this would be when light travels into the water. When light hits the water it slows down, causing a change in speed and ultimately changing the direction, causing a light refraction to occur.

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Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.

Gelneren [198K]

The average speed between 0 h and 2.340 h is 6.97 Km/h

Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.

$Average \: speed = \frac{total \: distance}{total \: time} \\ \\$

With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:

Total time = 2.340 – 0 = 2.340 h
Total distance = 16.3 – 0 = 16.3 Km
Average speed =?

$Average \: speed = \frac{total \: distance}{total \: time} \\ \\Average \: speed = \frac{16.3}{2.340} \\ \\ Average \: speed = 6.97 \: Km/h \\ \\$

Learn more about average speed: brainly.com/question/24884027

8 0

2 years ago

Which region of a longitudinal wave is this?

ipn [44]

I think the correct answer is is D.

8 0

2 years ago

Does calm water have a regular reflection or a diffuse reflection

Shtirlitz [24]

A regular relflection

8 0

3 years ago

Read 2 more answers

In our solar system, most asteroids are found _____.A.In the kuiper beltb.Orbiting close to the sunc.Between mars and jupiterd.B

nydimaria [60]

Between Mars and Jupiter

7 0

3 years ago

Read 2 more answers

Show that the electric potential along the axis of a uniformly charged disk of radius R and charge density sigma is given by by

OlgaM077 [116]

Explanation:

Area of ring $\ 2{\pi} a d a$

Charge of on ring $d q=-(\ 2{\pi} a d a)$

Charge on disk

$Q=-\left(\pi R^{2}\right)$

$\begin{aligned}d v &=\frac{k d q}{\sqrt{x^{2}+a^{2}}} \\&=2 \pi-k \frac{a d a}{\sqrt{x^{2}+a^{2}}} \\v(1) &=2 \pi c k \int_{0}^{R} \frac{a d a}{\sqrt{x^{2}+a^{2}}} \cdot_{2 \varepsilon_{0}}^{2} R \\&=2 \pi \sigma k[\sqrt{x^{2}+a^{2}}]_{0}^{2} \\&=\frac{2 \pi \sigma}{4 \pi \varepsilon_{0}}[\sqrt{z^{2}+R^{2}}-(21)] \\&=\frac{\sigma}{2}(\sqrt{2^{2}+R^{2}}-2)\end{aligned}$

Note: Refer the image attached

8 0

3 years ago