Which equation would you use to solve the following problem? An object is moved 29 m with a force of 289 N. What is the work don
1 answer:
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Answer:
783 grams
Explanation:
Here mass is given in kg
Some of the prefixes of the SI units are
1 gram = 10⁻³ kilogram
1 milligram = 10⁻⁶ kilogram
1 microgram = 10⁻⁹ kilogram
1 nanogram = 10⁻¹² kilogram
The number is 0.783
Here, the only solution where the number of significant figures is three is gram. If any other prefix is chosen then the significant figures will increase
So, 0.783 kg = 783 grams
Answer:
The speed of the car when load is dropped in it is 17.19 m/s.
Explanation:
It is given that,
Mass of the railroad car, m₁ = 16000 kg
Speed of the railroad car, v₁ = 23 m/s
Mass of additional load, m₂ = 5400 kg
The additional load is dropped onto the car. Let v will be its speed. On applying the conservation of momentum as :
v = 17.19 m/s
So, the speed of the car when load is dropped in it is 17.19 m/s. Hence, this is the required solution.