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ruslelena [56]
3 years ago
9

What is a force field

Physics
1 answer:
amid [387]3 years ago
3 0
Chiefly in science fiction) an invisible barrier of exerted strength or impetus.
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You work for the city water department and need to pump 3400 liters/minute of water from a tank at ground level into a vented (i
umka21 [38]

Answer:

P_E=46.2778\ kW

v=1.804\ m.s^{-1}

Explanation:

Given:

  • flow rate of water, \dot{V}=3400\ L.min^{-1}=3.4\ m^3.min^{-1}

<em>∵Density of water is 1 kg per liter</em>

∴mass flow rate of water, \dot{m}=3400\ kg.min^{-1}

  • height of pumping, h=75\ m
  • efficiency of motor drive, \eta=0.9
  • diameter of pipe, D =0.2\ m

<u>Now the power required for pumping the water at given conditions:</u>

P=\dot{m}.g.h

P=\frac{3400}{60} \times 9.8\times 75

P=41650\ W

<u>Hence the electric power required:</u>

P_E \times \eta=P

P_E \times 0.9=41650

P_E=46.2778\ kW

<u>Flow velocity is given as:</u>

v=\dot{V}\div a

where: a = cross sectional area of flow through the pipe

v=\frac{3.4}{60}\div (\pi.\frac{0.2^2}{4} )

v=1.804\ m.s^{-1}

3 0
3 years ago
What does a cell division allow all multicellular organisms to do
Levart [38]
I believe that the answer should be B. It makes the most sense to me.
4 0
3 years ago
Why does conduction occur more slowly in gases than in solids?​
Nataly [62]
Onduction in gas is slower than in liquids and solids because the particles in a gas collide less often. Conduction in metals is faster because the electrons are free to move about
4 0
3 years ago
Why does the entropy of a gas increase when it expands into a vacuum? Why does the entropy of a gas increase when it expands int
Mrrafil [7]

Answer:

The entropy of a gas increases when it expands into a vacuum because the number of possible states increases .

Explanation:

When a gas expand in a vacuum, the molecules of the gases vibrates very fast and starting moving with higher velocity in random directions which means the level of disorder in the gases increases.

Now the possible state of the gas molecule increases such as the particle can be located at different position due to increased randomness.

<u>Entropy is the measure of this randomness and thus with this increased randomness entropy also increases.</u>

6 0
3 years ago
A ball of mass 0.150 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.665 m. W
Liula [17]

Answer:

Impulse is 1.239 kg.m/s in upward direction

Explanation:

Taking upward motion as positive and downward motion as negative.

Downward motion:

Given:

Mass of ball (m) = 0.150 kg

Displacement of ball (S) = -1.25 m

Initial velocity (u) = 0 m/s

Acceleration is due to gravity (g) = -9.8 m/s²

Using equation of motion, we have:

v_d^2=u^2+2aS\\\\v=\pm\sqrt{u^2+2aS}\\\\v_d=\pm\sqrt{0+2\times -9.8\times -1.25}\\\\v_d=\pm\sqrt{24.5}=\pm4.95\ m/s

Since, the motion is downward, final velocity must be negative. So,

v_d=-4.95\ m/s

Upward motion:

Given:

Displacement of ball (S) = 0.665 m

Initial velocity (v_d) = 4.95 m/s(Upward direction)

Acceleration is due to gravity (g) = -9.8 m/s²

Using equation of motion, we have:

v_{up}^2=v_d^2+2aS\\\\v_{up}=\pm\sqrt{v_d^2+2aS}\\\\v_{up}=\pm\sqrt{24.5+2\times -9.8\times 0.665}\\\\v_{up}=\pm\sqrt{10.966}=\pm3.31\ m/s

Since, the motion is upward, final velocity must be positive. So,

v_{up}=3.31\ m/s

Now, impulse is equal to change in momentum. So,

Impulse = Final momentum - Initial momentum

J=m(v_{up}-v_d)\\\\J=(0.150\ kg)(3.31-(-4.95))\ m/s\\\\J=0.150\ kg\times 8.26\ m/s\\\\J=1.239\ Ns

Therefore, the impulse given to the ball by the floor is 1.239 kg.m/s in upward direction.

5 0
3 years ago
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