Calculate the kinetic energy of a 0.032 kg ball as it leaves a hand to be thrown upwards at 6.2 m/s
1 answer:
Answer:
The ball will have a kinetic energy of 0.615 Joules.
Explanation:
Use the kinetic energy formula
The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)
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Answer:
Explanation:
The velocity v₁ can be calculated with the kinematic formula:
Since the object is initially at rest, v₁ becomes:
Where g is the acceleration due to gravity. Now, the velocity v₂ can be calculated with the same formula, but now the initial velocity is v₁:
Substituting v₁ in this expression and solving for v₂, we get:
Now, dividing v₂ over v₁, we get the expression:
It means that v₂ is √2 times v₁.
Answer:
Explanation:
Given
mass of book(m)=2.1 kg
height up to which book is lifted is (h)2.2 m
height of person
Potential energy of book relative to ground=mgh
(b)PE w.r.t to person head =mg(h-h0)
work done by person in lifting box 2.2 m w.r.t floor
Word done =Potential Energy of box relative to floor=45.2 J
Answer:
The electric force between them is 878.9 N
Explanation:
Given:
Identical charge C
Separation between two charges m
For finding the electrical force,
According to the coulomb's law
Here, force between two balloons are repulsive because both charges are same.
Where
N
Therefore, the electric force between them is 878.9 N