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FrozenT [24]
3 years ago
14

Calculate the kinetic energy of a 0.032 kg ball as it leaves a hand to be thrown upwards at 6.2 m/s

Physics
1 answer:
AnnZ [28]3 years ago
3 0

Answer:

The ball will have a kinetic energy of 0.615 Joules.

Explanation:

Use the kinetic energy formula

E_k = \frac{1}{2}mv^2 = \frac{1}{2}0.032kg\cdot 6.2^2 \frac{m^2}{s^2}= 0.615J

The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)

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True or false conceptual physics 2 questions from chapter 25.
Arlecino [84]

Answer:

Explanation:

1) TRUE; potential difference can be calculated using path integral. Since the electric field is a conservative, the potential difference can be calculated using any path.

2) TRUE; since potential due to a charge is inversely dependent on distance, at infinity the potential will be almost zero.

3) TRUE, W = q.VBA.

4) FALSE; eV is a unit for work (or) energy.

5) TRUE; since the electric force is conservative force. There will be no loss in energy, the decreased potential energy will be coverted to kinetic energy.

6) FALSE; in the direction of electric field the potential decreases.

7) FALSE; equipotential surface is perpendicular to the electric field lines.

8) FALSE; electrostatic potential is scalar quantity. It depends only on the charge and distance from it.

9) FALSE; Inside a conductor the electric field is zero but the electric potential is constant at the value that is at the surface of the conductor.

10) TRUE; as long as the field is being measured outiside the body the bodies act as point charges. So electric fields due to all types of bodies charged identically will be equal.

3 0
3 years ago
If you speed through a construction zone while workers are present, your fines could be:.
valina [46]

If you speed through a construction zone while workers are present, your fines could be as much as one thousand dollars.

<h3>What is a Fine?</h3>

This is referred to as the amount which is instructed by a court or authority to be paid as a result of it being a penalty for various types of offences. each crime has its specific fine which helps to serve as deterrent for unlawful behavior in the community.

it is always best not to speed when within a construction zone which has workers present in the area. This is ideal as it helps to prevent incidences of accidents or death.

it is therefore the reason why a fine of 1000 dollars is to be paid so that people can think of such high amount before performing certain types of activities when driving and makes it the most appropriate choice.

Read more about Fine here brainly.com/question/25229258

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6 0
2 years ago
25 POINTS !!!! PLS HELP
Yuliya22 [10]

Answer:

G

Explanation

The acceleration of gravity is constant, and = 9.8 m/s² , no matter what mass of the object is. Initial speed for both objects = 0 m/s. So, after 2 sec the objects will have the same speed and the same distance.

Answer G: speed=v, distance =d.

5 0
3 years ago
A 0.305 kg book rests at an angle against one side of a bookshelf. The magnitude and direction of the total force exerted on the
tankabanditka [31]

Answer

given,

F_L= 1.52\ N

\theta_L= 31^0

mass of book = 0.305 Kg

so, from the diagram attached  below

F_L cos {\theta_L} + F_b sin {\theta_b} = m g

1.52 times cos {31^0} + F_b sin {\theta_b} = 0.305 \times 9.8

F_b sin {\theta_b} = 2.989 -1.303

F_b sin {\theta_b} = 1.686

computing horizontal component

F_b cos {\theta_b} = F_L sin {\theta_L}

cos {\theta_b} = \dfrac{F_L sin {\theta_L}}{F_b}

cos {\theta_b} = \dfrac{1.52 \times sin {31^0}}{1.686}

cos {\theta_b} = 0.464

θ = 62.35°

5 0
3 years ago
Helppppo!!!
goldfiish [28.3K]

Answer:

Electric force = 3.15\times 10^{-11}\textrm{ N}.

Explanation:

Given:

Charge on one grain, q_{1}=6\times 10^{-10}\textrm{ C}

Charge on second grain, q_{2}=2.3\times 10^{-15}\textrm{ C}

Distance between the two grains is, r=2\textrm{cm}=0.02\textrm{ m}

Electric force acting between two charges q_{1}\textrm{ and }q_{2} separated by a distance r is:

F_{e}=\frac{kq_{1}q_{2}}{r^2}

Where, k is Coulomb's constant equal to 9\times 10^9\textrm{ }Nm^2/C^2.

Now, plug in the given values and solve for F{e}.

F{e}=\frac{9\times 10^9\times 6.0\times 10^{-10}\times 2.3\times 10^{-15}}{(0.02)^2}\\\\F_{elec}=3.15\times 10^{-11}\textrm{ N}

Therefore, the electric force between them is 3.15\times 10^{-11}\textrm{ N}.

5 0
3 years ago
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