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alexgriva [62]
3 years ago
14

It is friction that provides the force for a car to accelerate, so for high-performance cars the factor that limits acceleration

isn’t the engine; it’s the tires. For typical rubber-on-concrete friction, what is the shortest time in which a car could accelerate from 0 to 60 mph?
Physics
1 answer:
bearhunter [10]3 years ago
6 0

Answer:

About 12 seconds

Explanation:

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Express force in terms of base units​
denis-greek [22]

Answer:

F = [MLT⁻²]

Explanation:

Force = ma

m (mass) = [M]

a (acceleration) = [LT⁻²]

F(force) = m x a = [MLT⁻²]

3 0
2 years ago
The longer the time between the arrival of the P-wave and S-wave, the _______ is the epicenter.
Brrunno [24]

The longer the time between the arrival of the P-wave and S-wave, the <u>farther away</u> is the epicenter.

<h3>What is epicenter and the relation between P-wave and S-wave?</h3>
  • The point on the earth's surface vertically above the hypocenter (or focus), point in the crust where a seismic rupture begins is said to be epicenter.
  • There are two types of waves during earthquakes, they are:
  1. P - wave
  2. S - wave
  • Each seismograph records the times when the first (P waves) and second (S waves) seismic waves arrive.
  • From the graph, through the information, scientists can determine how fast the waves are traveling.
  • The longer the time between the arrival of the P-wave and S-wave, the farther away is the epicenter.

Hence, Option B is the correct answer.

Learn more about epicenter,

brainly.com/question/28136716

#SPJ1

7 0
2 years ago
Ahh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahha aggg agg
timama [110]

shhhh hahahaha ahhhhhhhh ahhhh

4 0
3 years ago
Read 2 more answers
The magnetic flux through each turn of a 110-turn coil is given by ΦB = 9.75 ✕ 10−3 sin(ωt), where ω is the angular speed of the
Xelga [282]

Answer:

Explanation:

Given that a coil has a turns of

N = 110 turns

And the flux is given as function of t

ΦB = 9.75 ✕ 10^-3 sin(ωt),

Given that, at an instant the angular velocity is 8.70 ✕ 10² rev/min

ω = 8.70 ✕ 10² rev/min

Converting this to rad/sec

1 rev = 2πrad

Then,

ω = 8.7 × 10² × 2π / 60

ω = 91.11 rad/s

Now, we want to find the induced EMF as a function of time

EMF is given as

ε = —NdΦB/dt

ΦB = 9.75 ✕ 10^-3 sin(ωt),

dΦB/dt = 9.75 × 10^-3•ω Cos(ωt)

So,

ε = —NdΦB/dt

ε = —110 × 9.75 × 10^-3•ω Cos(ωt)

Since ω = 91.11 rad/s

ε = —110 × 9.75 × 10^-3 ×91.11 Cos(91.11t)

ε = —97.71 Cos(91.11t)

The EMF as a function of time is

ε = —97.71 Cos(91.11t)

Extra

The maximum EMF will be when Cos(91.11t) = -1

Then, maximum emf = 97.71V

8 0
3 years ago
Which phrase best describes wave motion
White raven [17]

Answer:

I would describe wave motion as “propagating oscillations” as a general phrase.

For something like water waves, I would say “water waves are oscillations of the surface of a body of water that propagate in a given direction.”

For electromagnetic waves I would say “An electromagnetic wave is an oscillating disturbance of the electric and magnetic fields that propagates through space.”

Explanation:

PLZ MARK BRAINLIEST

4 0
3 years ago
Read 2 more answers
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