Question

A 0.22 caliber handgun fires a 1.9g bullet at a velocity of 765m/s. Calculate the de Broglie wavelength of the bullet. Is the wave nature of matter significant for the bullets?

Answer 1

Answer:

• de Broglie wavelength of the bullet is 4.56 x 10⁻³⁴ m

• The value of the wavelength shows that wave nature of matter is insignificant for the bullet because it is larger than particles.

Explanation:

Given;

mass of the bullet, m = 1.9 g = 0.0019 kg

velocity of the bullet, v = 765 m/s

de Broglie wavelength of the bullet is given by;

$\lambda = \frac{h}{mv}$

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

λ is de Broglie wavelength of the bullet

$\lambda = \frac{h}{mv}\\\\ \lambda =\frac{(6.626*10^{-34})}{(0.0019)(765)}\\\\ \lambda =4.56 *10^{-34} \ m$

Thus, this value of the wavelength shows that wave nature of matter is insignificant for the bullet because it is larger than particles.