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Mazyrski [523]
3 years ago
8

A particle undergoes a constant acceleration of 3.90 m/s2. After a certain amount of time, its velocity is 12.2 m/s. (Where appl

icable, indicate the direction with the sign of your answer.) (a) If its initial velocity is 6.1 m/s, what is its displacement during this time?
Physics
1 answer:
Law Incorporation [45]3 years ago
8 0

Answer:

s_{f} = 14.312 m

Explanation:

Since the particle is experimenting a constant acceleration, the displacement can be found by using this formula:

v_{f}^{2} = v_{o}^{2} + 2 \cdot a \cdot (s_{f} - s_{o})

Since s_{o} = 0 m, the equation is simplified to this form:

v_{f}^{2} = v_{o}^{2} + 2 \cdot a \cdot s_{f}

Then, the displacement is now isolated:

s_{f} = \frac{v_{f}^{2}-v_{o}^{2}}{2 \cdot a}

Terms are replaced herein:

s_{f} = \frac{(12.2 \frac{m}{s})^{2}-(6.1 \frac{m}{s})^{2}}{2 \cdot (3.90 \frac{m}{s^{2}}) } \\s_{f} = 14.312 m

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2 years ago
uppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 9 ounces and a standard deviation of 0.8 ou
Brrunno [24]

Answer:

x= 9.53 ounces

Explanation:

Given that

Mean ,μ= 9 ounces

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He wants to sell only those potatoes that are among the heaviest 25%.

P=25% = 0.25

When P= 0.25 then Z=0.674

Lest take x is the the minimum weight required to be brought to the farmer's market.

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3 years ago
Which characteristic do all minerals have in common?
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Answer:

Five Characteristics of a Mineral

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These are just some examples.

Explanation:

7 0
3 years ago
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A person is riding on a Ferris wheel. When the wheel makes one complete turn, the net work done on the person by the gravitation
lara31 [8.8K]

Answer:

0

Explanation:

m = Mass of person

g = Acceleration due to gravity = 9.81 m/s²

d = Vertical height from the ground

F = Force = Weight = mg

Net work done would be

W_n=W_{up}+W_{down}\\\Rightarrow W_n=Fdcos180+Fdcos0\\\Rightarrow W_n=-mgd+mgd\\\Rightarrow W_n=0

Hence, the work done on the person by the gravitational force is 0

7 0
3 years ago
physics A river flows at a speed vr = 5.37 km/hr with respect to the shoreline. A boat needs to go perpendicular to the shorelin
vova2212 [387]

Answer: Vb is the vector  (-5.37m/s,  8.59 m/s), with a module 10.13m/s

then the ratio Vb/Vr = 10.13m/s/5.37m/s = 1.9

Explanation:

We can use the notation (x, y) where the river flows in the x-axis and the pier is on the y-axis.

We have Vr = (5.37m/s, 0m/s)

Now, if the boat wants to move only along the y-axis (perpendicularly to the shore).

The velocity of the boat Vb will be:

Vb = (-c*sin(32). c*cos(32))

Then we should have that:

5.37 m/s - c*sin(32) = 0

c = (5.37/sin(32))m/s = 10.13 m/s

the velocity in the y-axis is:

10.13m/s*cos(32) = 8.59 m/s

So Vb = (-5.37m/s,  8.59 m/s)

the ratio Vb/Vr = 10.13m/s/5.37m/s = 1.9 where i used Vb as the module of the boat's velocity.

7 0
3 years ago
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