Answer:
A 100 N force acting on a lever 2 m from the fulcrum balances an object 0.5 m from the fulcrum on. ... What is the weight of the object(in newtons)? What is its mass (in kg)? ... mass at the one end and effort arm is the distance between pivot and effort applied at the other end.
Explanation:
hpoe this helps you.
Answer:
A proposed answer to a s scientific problem is a hypothesis.
Answer:
C) 1.0 m
Explanation:
The component of the velocity parallel to the sidewalk is:
vₓ = v cos θ
vₓ = 0.1 m/s cos 45°
vₓ = 0.0707 m/s
The distance traveled after 14 seconds is:
d = vₓ t
d = (0.0707 m/s) (14 s)
d = 0.99 m
Closest answer is C) 1.0 m.
Answer: the image distance is -18, 28 cm this means behind of the concave mirror. The image size is 2.2 higher that the original so it has 8.8 cm with the same orientation as original and it is a virtual imagen.
Explanation: In order to sove the imagen formation for a concave mirror we have to use the following equation:
1/p+1/q=1/f where p and q represents the distance to the mirror for the object and imagen, respectively. f is the focal length for the concave mirror.
replacing the values we obtain:
1/8.3+1/q=1/15.2
so 1/q=(1/15.2)-(1/8.3)=-54.7*10^-3
then q=-18.28 cm
The magnification is given by M=-q/p=-(-18,28)/8.3= 2.2
We also add a picture to see the imagen formation for this case.