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2 years ago

Will the sun ever stop shining? If so, how and when would we know((there are 3 questions

Physics

1 answer:

Alinara [238K]2 years ago

6 0

Answer:

Explanation:stop it cause the sun don't shine that long unless if it's summer cause the summer time is very hot it may be 100 degrees or lower

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A 50.0-g object connected to a spring with a force constant of 35.0 n/m oscillates with an amplitude of 4.00 cm on a frictionles

Dimas [21]

A) The total energy of the system is sum of kinetic energy and elastic potential energy:
$E=K+U= \frac{1}{2}mv^2 + \frac{1}{2}kx^2$
where
m is the mass
v is the speed
k is the spring constant
x is the elongation/compression of the spring

The total energy is conserved, so we can calculate its value at any point of the motion. If we take the point of maximum displacement:
$x=A=4.00 cm = 0.04 m$
then the velocity of the system is zero, so the total energy is just potential energy, and it is equal to
$E=U= \frac{1}{2}kA^2 = \frac{1}{2}(35.0 N/m)(0.04 m)^2=0.028 J$

b) When the position of the object is
$x=1.00 cm = 0.01 m$
the potential energy of the system is
$U= \frac{1}{2}kx^2 = \frac{1}{2}(35.0 N/m)(0.01 m)^2 = 1.75 \cdot 10^{-3} J$
and so the kinetic energy is
$K=E-U=0.028 J - 1.75 \cdot 10^{-3}J =0.026 J$
since the mass is $m=50.0 g=0.05 kg$ , and the kinetic energy is given by
$K= \frac{1}{2}mv^2$
we can re-arrange the formula to find the speed of the object:
$v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2 \cdot 0.026 J}{0.05 kg} }=1.02 m/s$

c) The potential energy when the object is at
$x=3.00 cm=0.03 m$
is
$U= \frac{1}{2}kx^2 = \frac{1}{2}(35.0 N/m)(0.03 m)^2 =0.016 J$
Therefore the kinetic energy is
$K=E-U=0.028 J-0.016 J = 0.012 J$

d) We already found the potential energy at point c, and it is given by
$U= \frac{1}{2}kx^2 = \frac{1}{2}(35.0 N/m)(0.03 m)^2 =0.016 J$

5 0

3 years ago

A steel cable has a cross-sectional area 2.54 10-3 m2 and is kept under a tension of 1.01 104 N. The density of steel is 7860 kg

ElenaW [278]

Answer:

The speed is equals to 22.49 m/s

Explanation:

Given Data:

$Area = A=2.54*10^-^3m^2\\Force = F = 1.01*10^4N\\density = p = 7860 kg/m^3$

Required:

Speed of Traverse wave = c =?

Solution:

As we know that

$p=m/V\\\\ p=m/(L*A)\\p*A=m/L$

Now the equation for speed of traverse wave is calculated through:

$\sqrt \frac{F*L}{m}\\$

= $\sqrt\frac{F}{m/L} \\\sqrt{} \frac{F}{p*A}$

Substituting the values

$\sqrt\frac{1.01*10^4}{7860*2.54*10^-^3} \\$

=22.49 m/s

4 0

3 years ago

Suppose you first walk 12.0 m in a direction 200 west of north and then 20.0 m in a direction 40.00 south of west. How far are y

Tpy6a [65]

Complete Question

The complete question is shown on the first uploaded image

Answer:

the compass direction of the resultant displacement is $\theta =4.7^o$ south of west

Explanation:

Generally using cosine we can obtain the resultant R as follows

$R^2 = A^2 + B^2 -2ABcos(70)$

=> $R = \sqrt{12^2 + 20^2 - 2(12 ) * (20) cos 70}$

=> $R = 19.48 \ m$

We can obtain the direction of the resultant by first using sine rule to obtain angle C as follows

$\frac{A}{sin C} = \frac{R}{sin70 }$

=> $C= sin ^{-1} [\frac{A * (sin 70)}{R} ]$

=> $C = sin ^{-1} [\frac{20 * (sin 70)}{19.48} ]$

=> $C = 74.7 ^o$

Then the direction is obtained as

$\theta = C - 70$

=> $\theta = 74.7 - 70$

=> $\theta =4.7^o$

Hence the compass direction of the resultant displacement is $\theta =4.7^o$ south of west

7 0

2 years ago

This problem has been solved!

dalvyx [7]

Answer:

A. Workdone by helium, W = -1.829KJ

B. Internal energy, DE = 25.271KJ

Explanation:

Workdone can be defined as the force moving through a distance. For a gaseous system, when the volume of the gas expands, the system is losing energy. Therefore,

W = -P*DV

Where P is the pressure in pascal

DV is the change in volume in m3

DV = Vfinal - Vinitial

= 23.70 - 5.30

= 18.4L

W = -(0.981 * 18.4)

= -18.0504L.atm

Converting L.atm to joule,

= -18.0504 * 101.325

= -1828.97J

= -1.829KJ

If the system loses heat, Q the rection occurring is Exothermic.

Heat is the transfer of energy from one system to another.

Q = mcDT

Where m is the mass of the system

C is the specific heat capacity

Q = 27.20KJ

Internal energy is the summation of the heat supplied to a system and the workdone by the system

DE = Q + W

DE = 27.10 + (-1.829)

= 25.27KJ

8 0

2 years ago

Do non metals have luster

puteri [66]

Yes, It probably true. Because the Luster it has a nonmetal, is going to be found in periodic table.

Hope it helped you.

-Charlie

4 0

2 years ago