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Zarrin [17]
3 years ago
6

Which object will have the greatest change in

Physics
1 answer:
Brut [27]3 years ago
4 0
(4) a metal sphere with a charge of 1.0 × 10^−9 C <span>moved through a potential difference of 4.0 V would undergo the greatest change in electrical energy from the list. </span>
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what is the size of the force needed to change the momentum of an object 2000 kg m/s over a time period of 0.5 seconds?
dybincka [34]

Impulse is equal to change in momentum of an object.  The only way to change an object's momentum is to apply a force for certain amount of time.

Impulse is calculated as follows:  Δp = F * t

Put your values in the right spots and solve for F. In this case since F is multiplied by Time, you will divide both sides by the time to find your answer.

6 0
4 years ago
A car is traveling due north at 23.6 m&gt;s.
alexira [117]

A car is traveling due north at 23.6 m>s.

Find the velocity of the car after 7.10 s if its

acceleration is

The acceleration is known to be: a(t) = 1.7 m/s2.

We must integrate over time to obtain the velocity function, and the results are:

v(t) = (1.7m/s^2)

*t + v0

If we suppose that we begin at 23.6 m/s, then the initial velocity is: v0 = 23.6 m/s, where v0 is the beginning velocity.

The velocity formula is then: v(t) = (1.7m/s2).

*t + 23.6 m/s

We now seek to determine the value of t such that v(t) = 27.8 m/s.

Consequently, v(t) = 27.8 m/s = (1.7 m/s2)

*t + 23.6 m/s = (1.7 m/s2) 27.8 m/s - 23.6 m/s

t = 2.5 seconds when *t 4.2 m/s = (1.7 m/s/2)

At such acceleration, 2.5 seconds are required.

To learn more about acceleration Visit :

brainly.com/question/19599982

#SPJ9

4 0
2 years ago
How many joules of energy are required to accelerate one kilogram of mass from rest to a velocity of 0.866c?
Arlecino [84]

Answer:

the amount of energy needed is 1.8 x 10¹⁷ J.

Explanation:

Given;

mass of the object, m₀ = 1 kg

velocity of the object, v = 0.866 c

By physics convection, c is the speed of light = 3 x 10⁸ m/s

The energy needed is calculated as follows;

E = Mc²

As the object approaches the speed of light, the change in the mass of the object is given by Einstein's relativity formula;

M = \frac{M_0}{\sqrt{1- \frac{v^2}{c^2} } } \\\\  M = \frac{1}{\sqrt{1- \frac{(0.866c)^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{1- \frac{0.74996c^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{0.25} } \\\\ M = 2 \ kg

The energy required is calculated as;

E = 2 x (3 x 10⁸)²

E = 1.8 x 10¹⁷ J

Therefore, the amount of energy needed is 1.8 x 10¹⁷ J.

3 0
3 years ago
ILL GIVE THE BEST ANSWER BRAINLIEST I PROMISE AND ILL THANK EVERY ANSWER A polar bear is able to walk on ice without breaking it
krek1111 [17]

Answer:

Polar bears (Ursus maritimus) are of special interest because of their large size, white color and position as the top-level carnivore in the remote arctic environment. They occur only in the northern hemisphere nearly always in association with sea ice. They have only two colors of fur: tan and white. Polar bears were created to withstand cold temperatures and are quite adaptable. Polar bears are ferocious and the most dangerous of bears. They can lop a person's head off with one swoop of their paw.

5 0
3 years ago
Read 2 more answers
A radar station sends out a 250000 Hz sound wave at a speed of 340 m/s. The sound wave bounces off a weather ballon and returns
Eddi Din [679]

Answers:

a)The balloon is 68 m away of the radar station

b) The direction of the balloon is towards the radar station

Explanation:

We can solve this problem with the Doppler shift equation:

f'=\frac{V+V_{o}}{V-V_{s}} f  (1)

Where:

f=250,000 Hz is the actual frequency of the sound wave

f'=240,000 Hz is the "observed" frequency

V=340 m/s is the velocity of sound

V_{o}=0 m/s is the velocity of the observer, which is stationary

V_{s} is the velocity of the source, which is the balloon

Isolating V_{s}:

V_{s}=\frac{V(f'-f)}{f'}  (2)

V_{s}=\frac{340 m/s(240,000 Hz-250,000 Hz)}{240,000 Hz}  (3)

V_{s}=-14.16 m/s (4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.

Now that we have the velocity of the balloon (hence its speed, the positive value) and the time (t=4.8 s) given as data, we can find the distance:

d=V_{s}t (5)

d=(14.16 m/s)(4.8 s) (6)

Finally:

d=68 m (8) This is the distance of the balloon from the radar station

6 0
3 years ago
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