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3 years ago

What is the meaning of technology

1 answer:

5 0

The exact definition of technology is: The application of scientific knowledge for practical purposes, especially in industry.

The way I would put it is that technology isn’t just electronics, smartphones, and flying cars. Technology is information that people reveal and figure out and this is why it advances. You hear all the time the “advances in technology” and it’s a term that has grown rapidly. It helps businesses to progress, it’s taught people, it’s in some ways beneficial to people’s lives. It has many meanings and really that is technology simply put.

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A molecule of methane gas is shown. What do the red and blue dots represent? A) Protons being shared between the atoms. B) Elect

nalin [4]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The red and blue dots represent is

Protons being shared between the atoms. The answer is A>

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O Which two elements will be the most alike and why?

Pavel [41]

C. Because they are in the same group, so they have the same number of valence (outer) electrons

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Describe in detail how you might experimentally determine the density of a cylindrical shaped object. Explain all steps clearly

pashok25 [27]

Tbh idk I need help to

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4 years ago

A 5.00-kg object is attached to one end of a horizontal spring that has a negligible mass and a spring constant of 280 N/m. The

lina2011 [118]

Answer:

1) v = 0.45 m/s

2) v = 0.65 m/s

3) v = 0.75 m/s

Explanation:

1) We can find the speed of the object by conservation of energy:

$E_{i} = E_{f}$

$\frac{1}{2}kx^{2} = \frac{1}{2}kx^{2} + \frac{1}{2}mv^{2}$

Where:

k: is the spring constant = 280 N/m

v: is the speed of the object =?

m: is the mass of the object = 5.00 kg

x: is the displacement of the spring

$\frac{1}{2}280N/m(0.10 m)^{2} = \frac{1}{2}280N/m(0.08 m)^{2} + \frac{1}{2}5.00 kgv^{2}$

$v = \sqrt{\frac{280N/m(0.10 m)^{2} - 280N/m(0.08 m)^{2}}{5.00 kg}} = 0.45 m/s$

2) When the object is 5.00 cm (0.050 m) from equilibrium, the speed of the object is:

$\frac{1}{2}kx^{2} = \frac{1}{2}kx^{2} + \frac{1}{2}mv^{2}$

$\frac{1}{2}280N/m(0.10 m)^{2} = \frac{1}{2}280N/m(0.05 m)^{2} + \frac{1}{2}5.00 kgv^{2}$

$v = \sqrt{\frac{280N/m(0.10 m)^{2} - 280N/m(0.05 m)^{2}}{5.00 kg}} = 0.65 m/s$

3) When the object is at the equilibrium position, the speed of the object is:

$\frac{1}{2}kx^{2} = \frac{1}{2}kx^{2} + \frac{1}{2}mv^{2}$

$\frac{1}{2}280N/m(0.10 m)^{2} = \frac{1}{2}280N/m(0 m)^{2} + \frac{1}{2}5.00 kgv^{2}$

$v = \sqrt{\frac{280N/m(0.10 m)^{2}}{5.00 kg}} = 0.75 m/s$

I hope it helps you!

8 0

3 years ago

2. If a vehicle with four wheels is traveling in a linear path through soft dirt, how many and which tires would you expect to l

velikii [3]

Given our understanding of the situation, for this vehicle with four wheels is traveling in a linear path through soft dirt, we would expect for only two wheels to leave tire track impressions.

The vehicle has four wheels, and one might think initially that it makes sense for all four wheels to create tire track impressions on the dirt. This assessment is correct, all four tires will create impressions, However, not all four tires will leave a said impression.

This is due to the fact that as the vehicle advances, the tires in the back will erase the impressions left by the front tires. Therefore, only two tire track impressions will be left.

To learn more visit:

brainly.com/question/14443145?referrer=searchResults

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3 years ago