Recent findings on the topic of brain based research indicate all of the following except
1 answer:
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Answer:
v₁₀ = 1.90 m / s
Explanation:
In this exercise we are given the maximum height data, with energy we can know how fast the body came out
Final mechanical energy, maximum height
= U = m g h
Initial mechanical energy, in the lower part of the track
Em₀ = K = ½ m v²
Em=
½ m v² = m g h
v = √ 2gh
Now we can use the moment to find the speed with which objects collide
The large object has a mass M = 5.41 kg a velocity starts v₁₀, the small object has a mass m = 1.68 kg an initial velocity of zero v₂₀ = 0 and final velocity v
Initial before the crash
p₀ = M v₁₀ + 0
Final after the crash
= M v1f + m v
p₀ =
M v₁₀ = M + m v
As the shock is elastic the kinetic energy is conserved
K₀ =
½ M v₁₀² = ½ M ² + ½ m v²
Let's write the system of equations
M v₁₀ = M + m v
M v1₁₀² = M ² + m v²
We cleared v1f in the first we replaced in the second
= (M v₁₀ - mv) / M
M v₁₀² = M (M v₁₀ - mv)² / M² + m v²
M v₁₀² = 1 / M (M² v₁₀² - 2mM v v₁₀ + m² v²) +m v²
v₁₀² (M - M) + 2 m v v₁₀ - v² (m2 + m) / M = 0
2 m v₁₀ - v (m + 1) m/ M = 0
v₁₀ = v (m +1) / (2M)
Let's substitute the value of v
v1₁₀= √ (2gh) (m +1) / (2M)
Let's calculate
v₁₀ = √ (2 9.8 3) (1+ 1.68) / (2 5.41)
V₁₀ = 7.668 (2.68) / 10.82
v₁₀ = 1.90 m / s
Answer:
And the forces are equal but in the opposite direction. So then we can write by general rule:
Or equivalently:
Where: represent the speed of the car and
the speed of the ball
represent the mass of the car
represent the mass of the ball
Since the ball is moving to the left and we assume that the total momentum not changes then the car need to move to the right in order to satisfy the equation and satisfy the balance.
By conservation of the momentum the car will move to the right since the ball is moves to the left.
So then the correct option for this case is :
A.Yes, and it moves to the right.
Explanation:
If we assume that we have the situation in the figure attached.
For this case we assume that the momentum changes are equal in magnitude and opposite in direction, so then we satisfy this:
And the forces are equal but in the opposite direction. So then we can write by general rule:
Or equivalently:
Where: represent the speed of the car and
the speed of the ball
represent the mass of the car
represent the mass of the ball
Since the ball is moving to the left and we assume that the total momentum not changes then the car need to move to the right in order to satisfy the equation and satisfy the balance.
By conservation of the momentum the car will move to the right since the ball is moves to the left.
So then the correct option for this case is :
A.Yes, and it moves to the right.
