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Anestetic [448]
2 years ago
6

50 POINTS PLUS BRAINLIEST NEED HELP ASAP Please solve these 5 questions

Chemistry
1 answer:
MariettaO [177]2 years ago
4 0

Answer:

Argon 7.89693x10^25 atoms

Gold 4.1949252x10^25 atoms

Carbon Monoxide 34.55149 moles

Potassium oxide  1.6 moles

Calcium 4.4969x10^24 atoms

Explanation:

Its done with dimensional analysis i can not put the full work here because it would look to sloppy

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friction

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2 years ago
A chemist adds 215.0mL of a 6.0x10^−5/mmolL mercury(II) iodide HgI2 solution to a reaction flask. Calculate the micromoles of me
Snezhnost [94]

The micromoles of mercury(II) iodide : 0.013 μ moles

<h3>Further explanation</h3>

Given

215.0mL of a 6.0x10⁻⁵mmol/L HgI₂

Required

micromoles of HgI₂

Solution

Molarity(M) = moles of solute per liters of solution

Can be formulated :

M = n : V

n = moles

V = volume of solution

V = 215 mL = 0.215 L

so moles of solution :

n = M x V

n = 6.10 mmol/L x 0.215 L

n = 1.312 . 10⁻⁵ mmol

mmol = 10³ micromol

so 1.312 mmol = 1.312.10⁻⁵ x 10³ = 0.01312 micromoles ⇒ 2 sif fig = 0.013 μ moles

6 0
2 years ago
Can someone please help me, best answer gets BRAINLIEST
salantis [7]

Answer:

9839 is your answer mate .

Plz mark brainliest and follow me ❤❤❤❤

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