Jacket

Activation energy is (blank)

timurjin [86]

B. The energy barrier between reactants and products

hope this helps!

(:

7 0

3 years ago

Read 2 more answers

How many grams of aluminum oxide will you need to start with in order to make 6500 g of aluminum hydroxide?

kherson [118]

Answer:

Explanation:

2Al(s) + 3 2 O2(g) → Al2O3(s) And given the stoichiometry ...and EXCESS dioxygen gas...we would get 6.25⋅ mol of alumina. the which represents a mass... ...6.25 ⋅ mol ×101.96 ⋅ g ⋅ mol−1 molar mass of alumina ≡ 637.25 ⋅ g.

3 0

2 years ago

Read 2 more answers

Someone answer this please.

Nataly_w [17]

Answer: The percent composition of oxygen is 54.5%

Explanation:

Below I have attached my work through, but essentially the percent composition relies on finding the mass of the oxygens and dividing it by the mass of the whole compound. The masses of the elements can be found on the periodic table and added together to get a mass of the whole compound- ascorbic acid. Then, you turn this proportion into a percent by multiplying by 100%.

6 0

3 years ago

Read 2 more answers

Pls tell me how to solve this!

Anna35 [415]

Answer:

12 seconds

Explanation:

Time taken by 50cm³ of oxygen to diffuse from pinhole

= 1 minute = 60 seconds

⠀

$\textsf{ Rate of oxygen} \sf (O_2) = \frac{50}{60}$

⠀

Let time taken by 50cm³ of hydrogen to diffuse from pinhole = t seconds

⠀

$\textsf {Rate of hydrogen } \sf(H_2) = \frac{50}{t}$

⠀

According to the formula

$\sf \frac{Rate \: of \: hydrogen(H_2)}{Rate \: of \: oxygen(O_2) } = \sqrt{ \frac{Molar \: mass \: of \: O_2}{Molar \: mass \: of \: H_2} }$

⠀

$\large \sf \frac{50}{t} \div \frac{50}{60} = \sqrt{ \frac{\cancel{32}\small 16}{\cancel2} } \\ \\ \sf \large \frac{ \cancel{50}}{t} \times \frac{60}{ \cancel{50}} = \sqrt{16} \\ \\ \sf \large \frac{60}{t} = 4 \\ \\ \sf \large \frac{ \cancel{60} \: \small12}{ \cancel4} = t \\ \\ \large \underline{ \boxed{ \tt t = 12 \: seconds}}$

⠀

<h3>Henceforth, the time taken by 50cm³ of hydrogen to diffuse is 12 seconds. </h3>

⠀

<h2>Thank you!</h2>

8 0

2 years ago

When calcium carbonate is heated, it breaks down into calcium oxide and carbon dioxide.

Aleks [24]

The final answer is C

6 0

2 years ago