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3 years ago

If the force of a golf club on a golf ball is 200 N forward, what will the force of the ball on the club be?

Physics

2 answers:

AVprozaik [17]3 years ago

8 0

Answer:

it's b 200 n backward

Explanation:

Afina-wow [57]3 years ago

5 0

Newton's Third Law is every action has an equal and opposite reaction.

B. 200 N Backwards is the correct answer

The ball should put 200 N of force towards the golfer.

The ball is exerting 200 N of force towards the club as well, but the opposite reaction is that it flies away.

For more details: For each reaction there must be a opposite reaction(Which is the ball going 200 N backwards) and an equal reaction(The ball putting 200 N of force towards the golfer and the golfer)

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The dimensions of aluminum foil in a box for sale in super markets are 66 2/3 yards by 12 inches. the mass of the foil is 0.83 k

disa [49]

Length of the sheet is given as

$L = \frac{200}{3} yards = 6096 cm$

width of the sheet is given as

$w = 12 inches = 30.48 cm$

now let say its thickness is "t"

so the volume of the sheet is given as

$V = L*w*t$

$V = 6096*30.48* t$

$V = 185806.08*t cm^3$

mass of the sheet is given as

$m = 0.83 kg = 830 gram$

now we have

$density = \frac{mass}{volume}$

$2.70 = \frac{830}{185806.08*t}$

by solving above we have

$t = 1.65 * 10^{-3} cm$

so the thickness of sheet will be above

4 0

3 years ago

A 3.0 pF capacitor consists of two parallel plates that have surface charge densities of 1.0 nC/mm2 . If the potential between t

Archy [21]

Answer:

$A=81mm^2$

Explanation:

We know that for a capacitor $Q=CV$ , where Q is the charge of one plate, C the capacitance and V the potential between the plates.

We also know that $Q=\sigma A$ , since $\sigma$ is the surface charge density and A the area of the plate (both equal in our case).

Putting all together:

$A=\frac{CV}{\sigma}$

Which for our values is:

$A=\frac{(3\times10^{-12}F)(27\times10^3V)}{1\times10^{-9}C/mm^2}=81mm^2$

Where we notice that the S.I. units combination FV/C must not have units (we can verify it directly from their definitions or we notice that $mm^2$ is enough to describe an area).

8 0

3 years ago

India used 600 joules of work on a steel block and moved it 4.8 meters. How much forced was used ?

dangina [55]

The formula for finding force is F=W/d so then you plug in the numbers:
F=600/4.8
F=125N

8 0

3 years ago

A rock has a specific gravity of 2.32 and a volume of 8.64 in3 how much does it weigh

lianna [129]

Answer: 3.21 N

$Specific\hspace{1mm} gravity = \frac {Density\hspace{1mm}of\hspace{1mm}substance}{Density\hspace{1mm} of \hspace{1mm}water}$

$\Rightarrow Density \hspace{1mm}of\hspace{1mm}substance= 2.32\times 1000\hspace{1mm} kg/m^3 = 2320\hspace{1mm}kg/m^3\\ Mass =Density\times volume\\ \Rightarrow 2320 \hspace{1mm} kg/m^3\times 8.64 \hspace{1mm}in^3\times \frac {1.64\times10^{-5} m^3}{1\hspace{1mm}in^3}=0.328 kg$

For weight, we will multiply by $g=9.8 m/s^{-2}$

$weight= 0.328\times9.8=3.21\hspace{1mm}N$

Hence, the rock would weigh 3.21 N.

3 0

3 years ago

A mass is stretched 4 centimeters from the equilibrium position of a spring. If the displacement is doubled, what can be conclud

marta [7]

From Simple Harmonic Motion (SHM), the restoring force is given by:

F = -ω²x

We can see that restoring force is proportional to the displacement, x. So if the displacement x is doubled, then the restoring force will also be doubled.

8 0

3 years ago

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