Al = 26.981539u which rounds up to 27u
Ca= 40.078u which sounds to 40u
Sodium= 22.989769 which rounds up to 23u
Potassium= 39.0983u which rounds to 39u
Nitrogen= 14.0067u which rounds to 14u
Silicon= 28.0855 u which rounds to 28u
Iron= 55.845 u which rounds to 56u
Hydrogen= 1.00784 u which rounds to 1
I hope this helps!!
Answer:
2 ATP
Explanation:
glycolysis is the beginning of cellular respiration and it yielded net ATP of two produced from 1,3 bisphosphoglycerate conversion to 3-phosphoglycerate (2 ATP) and conversion of phosphoenolpyruvate to pyruvate ( 2ATP). One will recall that 2 ATP had been expended in the conversion of glucose to glucose-6-phosphate, and in the conversion of fructose-6-phosphate to fructose -1,6- bisphosphate. Other product of glycolysis are 2 NADH, 2 Pyruvate that may go into kreb cycle for further energy production depending on the organism type of respiration.
Answer:
<h2>11.2 g</h2>
Explanation:
Given,
Mass of P = 4.89 g
Molar mass of = 30.9738 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the reaction shown below as:-
4 moles of P on reaction forms 2 moles of diphosphorus pentoxide
Also,
1 mole of P on reaction forms 2/4 mole of diphosphorus pentoxide
0.158 moles of P on reaction forms moles of diphosphorus pentoxide
Moles of diphosphorus pentoxide = 0.079 moles
Molar mass of diphosphorus pentoxide = 141.9445 g/mol
<u>Mass = Moles * Molar mass = 0.079 moles * 141.9445 g/mol = 11.2 g</u>
<span>Chemical changes result in the formation of new substances, and the changes that occur cannot be reversed (at least without other chemical changes). The heat from frying an egg causes the egg's protein to change permanently in texture and in appearance through a process called denaturing.
The answer is B. Frying an egg.
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I haven't done these in some time, so I'm not sure if they are 100% right.
1) 6.3 moles of H2( 2 mol of NH3 / 3 mol of H2)= 4.2 mol of NH3
6.3 moles of H2( 2 mol of NH3/ 3 mol of H2)(17.04 g of NH3/1 mol NH3)= 71.57 g of NH3
2) 2.5 moles of N2(2 mol of NH3/1 mol of N2)= 5 moles of NH3
2.25 moles of N2(2 mol of NH3/ 1 mol of N2)(6.02x10^23 particles/ 1 mol of NH3)= 3.01x10^24 particles of NH3
3) 425 g of NH3(1 mol of NH3/17.04 g NH3)= 24.9 moles of NH3
425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)(28.02 g of N2/1 mol N2)= 349 g of N2
425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)= 12.5 mol of N2
4) 10 moles NH3(3 moles of H2/2 moles of NH3)= 15 moles H2
10 moles NH3(3 mol of H2/2 mol of NH3)(2.02 g of H2/1 mol of H2)= 30.3 g of H2
30.3 g = .0303 liters of H2