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3 years ago

What is the volume of a salt crystal measuring 1.64 x 10^-2m by 1.5 x 10^-2m by 4.8 x 10^-3

Chemistry

1 answer:

lubasha [3.4K]3 years ago

5 0

Answer:

V = 1.2 × 10⁻⁶ m³

Explanation:

Volume is equal to length × width × height, since we are given these measurements in the question we can simply plug our numbers into the formula.

V = l × w × h

V = 1.64 x 10⁻² × 1.5 x 10⁻² × 4.8 x 10⁻³

V = 1.2 × 10⁻⁶ m³

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Explain why the C―Ha bond is much more acidic than the C―Hb bond in pentan-2-one. Select the single best answer. 253 Ha is less

mafiozo [28]

Answer:

Ha is more acidic than Hb because loss of Ha forms a resonance-stabilized conjugate base.

Explanation:

The carbon atom that is next to the carbonyl group in pentan-2-one is known as the alpha carbon atom, this carbon atom bears the Ha, the alpha hydrogen atoms.

Ha is more acidic than Hb because, loss of Ha leads to the formation of a resonance stabilized enolate ion. This resonance stabilization of the ion formed makes loss of Ha an easier process than loss of Hb, hence the answer above.

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3 years ago

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2 years ago

Linda performed the following trials in an experiment. Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0

nexus9112 [7]

Answer: The correct answer is Option b.

Explanation:

To calculate the amount of heat absorbed or released, we use the following equation:

$q=mc\Delta T$ .....(1)

where, q = amount of heat absorbed or released.

m = mass of the substance

c = heat capacity of water = 4.186 J/g ° C

$\Delta T$ = Change in temperature

For Trial 1:

We are given:

$m=30g\\\Delta T=[40-0]^oC=40^oC\\q=?J$

Putting values in equation 1, we get:

$q=30g\times 4.186J/g^oC\times 40^oC$

q = 5023.2 J

For trial 2:

We are given:

$m=40g\\\Delta T=[40-30]^oC=10^oC\\q=?J$

Putting values in equation 1, we get:

$q=40g\times 4.186J/g^oC\times 10^oC$

q = 1674.4 J

Heat gained by Trial 1 than trial 2 = $(5023.2-1674.4)J=3347J$

Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.

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3 years ago

The element in group 4 and period 3

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2 years ago

Read 2 more answers

How much heat energy is required to melt 75g of ice at 0°C?

Mnenie [13.5K]

The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol. This means for every mole of ice we melt we must apply 6.02 kj of heat. We can calculate the heat needed with the following equation:

Q = N x ΔH

where:

Q = heat

N = moles

ΔH = enthalpy

In this problem we would like to calculate the heat needed to melt 35 grams of ice at 0 °C. This problem can be broken into three steps:

1. Calculate moles of water

2. multiply by the enthalpy of fusion

3. Convert kJ to J.

Step 1 : Calculate moles of water

$[ 75g ] x (\frac{1 mol}{18.02g} ) =$

Step 2 : Multiply by enthalpy of fusion

Q = N × ΔH =  [ Step 1 Answer ] × 6.02 =

Step 3 : Convert kJ to J

$[ Step 2 Answer ] x (\frac{1000j}{1kJ} ) =$

Finally rounding to 2 sig figs (since 34°C has two sig figs) we get

Q Would Equal ____

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2 years ago