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3 years ago

What is the volume of a salt crystal measuring 1.64 x 10^-2m by 1.5 x 10^-2m by 4.8 x 10^-3

Chemistry

1 answer:

lubasha [3.4K]3 years ago

5 0

Answer:

V = 1.2 × 10⁻⁶ m³

Explanation:

Volume is equal to length × width × height, since we are given these measurements in the question we can simply plug our numbers into the formula.

V = l × w × h

V = 1.64 x 10⁻² × 1.5 x 10⁻² × 4.8 x 10⁻³

V = 1.2 × 10⁻⁶ m³

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How many grams of NO can be produced if 204 g of NO2 is mixed with 58.1 g of H2O?

Goshia [24]

Answer:

44.4 grams of NO can be produced

Explanation:

Step 1: Data given

Mass of NO2 = 204 grams

Molar mass NO2 = 46.0 g/mol

Mass of H2O = 58.1 grams

Molar mass H2O = 18.02 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 204 grams / 46.0 g/mol

Moles NO2 = 4.43 moles

Step 4: Calculate moles H2O

Moles H2O = 58.1 grams / 18.02 g/mol

Moles H2O = 3.22 moles

Step 5: Calculate limiting reactant

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

NO2 is the limiting reactant. It will completely be consumed (4.43 moles). H2O is in excess. there will react 4.43 /3 = 1.48 moles. There will remain 3.22 - 1.48 = 1.74 moles

Step 6: Calculate moles NO

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 4.43 moles NO2 we'll have 4.43/3 = 1.48 moles NO

Step 7: Calculate mass NO

Mass NO = 1.48 moles * 30.01 g/mol

Mass NO = 44.4 grams

44.4 grams of NO can be produced

3 0

3 years ago

1. Which combinations of substances resulted in a chemical change?

MrRissso [65]

Answer:

. For each metal that participated in a chemical change, write the type of metal it is, based on yourexamination of the periodic table.Answer: Ammonium Vanadate appears to be mostly a post transition metal. Manganese sulfate also hasmore post transition atoms than transition atoms. Iron nitrate is a transition metal. The cobalt nitrate is atransition metal. Copper nitrate is a transition metal. Zinc nitrate is also a transition metal.(5 points)3. Were there any metallic compounds that did not react with either the acid or the base? Write the type ofmetal, based on your examination of the periodic table.4. Make a general statement about the reactivity of the metals in this experiment.Answer: The transition metals in this experiment were all reactive when mixed with one of the twosubstances. The alkali and alkaline earth metals, however, did not react at all.

Explanation:

6 0

3 years ago

a pure sample of a compound on combustion analysis gave 361 mg of CO2 and 147mg of H2O. if the weight of the sample is 202 mg ca

Colt1911 [192]

Answer:

$m_C=98.5mgC$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us obtain the mass of carbon in the sample by applying the following stoichiometric factor, considering that the only source of this atom in the sample is contained in the produced 361 mg of CO2 and one mole of this compound contain one mole of carbon atoms whose mass is 12.01 g/mol or mg/mmol as shown below:

$m_C=361mgCO_2*\frac{1mmolCO_2}{44.01mgCO_2}* \frac{1mmolC}{1mmolCO_2}*\frac{12.01mgC}{1mmolC} \\\\m_C=98.5mgC$