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4 years ago

Can someone plz help with this ASAP

Physics

1 answer:

ale4655 [162]4 years ago

6 0

Answer:

Explanation:

A does not make sense, because since electrons move towards positive change and are repelled by negative charge, they would move towards the smaller negative charge rather than the large one. This also rules out option D.

Option B could potentially be the answer, since during any kind of conduction the end goal is equilibrium, but if B is true than C must also be, and All of the Above is ruled out.

Option C makes the most sense because electrons seek out places where electron density is lower, so they can metaphorically "have more space for themselves"

Hope this helps!

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Which of the following statements BEST explains why ball-and-socket joints have the greatest range of motion? A. The contours of

vekshin1

The possible direction of movement of an object accounts for the motion.

The cup shape of the socket allows for nearly circular motion. Hence, option (D) is correct.

What is a Motion?

When an object tends to move from one point to another in a given interval of time, then the object is said to be in motion.

Ball-and-socket joints possess a rounded, ball-like end of one bone fitting into a cup-like socket of another bone. This system allows the greatest range of circular motion, as all movement types are possible in all directions.

Thus, we can conclude that the cup shape of the socket allows for nearly circular motion. Hence, option (D) is correct.

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3 years ago

A current of 17.0 mA is maintained in a single circular loop of 2.00 \mathrm{~m} circumference. A magnetic field of 0.800T is di

poizon [28]

The magnetic moment is -

M = 5.5 x $10^{-3}$ A $m^{2}$ .

We have current carrying single circular loop placed in a magnetic field

parallel to the plane of the loop.

We have to determine the Magnetic moment of the loop.

<h3>What is the formula to calculate the magnetic moment of loop?</h3>

The formula to calculate the magnetic moment of the loop is -

M = NIA

where -

N - Number of turns

I - Current in the loop

A - Area of the loop

According to the question, we have -

I = 17mA = 0.017A

Circumference (C) = 2 meters

B = 0.8 T

Now -

C = 2

2 $\pi$ r = 2

$\pi$ r = 1

r = $\frac{1}{\pi }$

r = 0.32

Using the formula -

M = NIA

M = $\pi$ NI $r^{2}$

M = 3.14 x 1 x 0.017 x 0.32 x 0.32

M = 3.14 x 4 x 0.017

M = 5.5 x $10^{-3}$ A $m^{2}$

Hence, the magnetic moment is -

M = 5.5 x $10^{-3}$ A $m^{2}$

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3 0

1 year ago

Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =

Sloan [31]

Answer:

The current is $I = 8.9 *10^{-5} \ A$

Explanation:

From the question we are told that

The radius is $r = 3.17 \ mm = 3.17 *10^{-3} \ m$

The current density is $J = c\cdot r^2 = 9.00*10^{6} \ A/m^4 \cdot r^2$

The distance we are considering is $r = 0.5 R = 0.001585$

Generally current density is mathematically represented as

$J = \frac{I}{A }$

Where A is the cross-sectional area represented as

$A = \pi r^2$

=> $J = \frac{I}{\pi r^2 }$

=> $I = J * (\pi r^2 )$

Now the change in current per unit length is mathematically evaluated as

$dI = 2 J * \pi r dr$

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

$I = 2\pi \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr$

$I = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr$

$I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.$

$I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]$

substituting values

$I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]$

$I = 8.9 *10^{-5} \ A$

5 0

4 years ago

Which list places different units of matter in the correct sequence from largest to smallest

weqwewe [10]

Answer:

What do you mean?

6 0

3 years ago

Read 2 more answers

2. Who bombarded molybdenum with atomic number (Z=42) with fast moving<br>neutrons?<br>

Dominik [7]

Answer:

This question appears incomplete

Explanation:

This question appears incomplete, however Molybdenum-99 (⁹⁹Mo) is produced by bombarding Molybdenum-98 (⁹⁸Mo) with fast moving neutrons (¹₀n) as shown below

⁹⁸₄₂Mo + ¹₀n ⇒ ⁹⁹₄₂Mo + ⁰₀γ

This reaction is a nuclear caption reaction (which occurs in a nuclear reactor) for the production of Molybdenum-99 (⁹⁹Mo) which serves as a "precursor" for the production of medically viable/ Clinical Grade Technutium-99m (⁹⁹Tc) through Ion-exchange technique.

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4 years ago