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777dan777 [17]
4 years ago
8

Can someone plz help with this ASAP

Physics
1 answer:
ale4655 [162]4 years ago
6 0

Answer:

C

Explanation:

A does not make sense, because since electrons move towards positive change and are repelled by negative charge, they would move towards the smaller negative charge rather than the large one. This also rules out option D.

Option B could potentially be the answer, since during any kind of conduction the end goal is equilibrium, but if B is true than C must also be, and All of the Above is ruled out.

Option C makes the most sense because electrons seek out places where electron density is lower, so they can metaphorically "have more space for themselves"

Hope this helps!

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The interference pattern seen when light passes through narrow, closely spaced slits, is due to
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<h2>Answer: Diffraction</h2><h2 />

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A cat runs and jumps from one roof top to another which is 5 m away and 3 m below. Calculate the minimum horizontal speed with w
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The vapor pressure of benzene, C6H6, is 40.1 mmHg at 7.6°C. What is its vapor pressure at 60.6°C? The molar heat of vaporization
ANEK [815]

Answer:

The vapor pressure at 60.6°C is 330.89 mmHg

Explanation:

Applying Clausius Clapeyron Equation

ln(\frac{P_2}{P_1}) = \frac{\delta H}{R}[\frac{1}{T_1}- \frac{1}{T_2}]

Where;

P₂ is the final vapor pressure of benzene = ?

P₁ is the initial vapor pressure of benzene = 40.1 mmHg

T₂ is the final temperature of benzene = 60.6°C = 333.6 K

T₁ is the initial temperature of benzene = 7.6°C = 280.6 K

ΔH is the molar heat of vaporization of benzene = 31.0 kJ/mol

R is gas rate = 8.314 J/mol.k

ln(\frac{P_2}{40.1}) = \frac{31,000}{8.314}[\frac{1}{280.6}- \frac{1}{333.6}]\\\\ln(\frac{P_2}{40.1}) = 3728.65 (0.003564 - 0.002998)\\\\ln(\frac{P_2}{40.1}) = 3728.65  (0.000566)\\\\ln(\frac{P_2}{40.1}) = 2.1104\\\\\frac{P_2}{40.1} = e^{2.1104}\\\\\frac{P_2}{40.1} = 8.2515\\\\P_2 = (40.1*8.2515)mmHg = 330.89 mmHg

Therefore, the vapor pressure at 60.6°C is 330.89 mmHg

6 0
4 years ago
Read 2 more answers
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