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Answer:
high tension: 4.2 × 1.5 = 6.3 cm/s
medium tension: 2.8 ×1.5 = 4.2 cm/s
low tension: 0.8 × 1.5 = 1.2 cm/s
Explanation: Given Settings:
amplitude: 0.75 cm
damping: zero
Using
Speed = frequency ×wavelength
Where
Wavelength = 0.75 × 2 = 1.5 cm
Therefore:
high tension: 4.2 × 1.5 = 6.3 cm/s
medium tension: 2.8 ×1.5 = 4.2 cm/s
low tension: 0.8 × 1.5 = 1.2 cm/s
Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :
F = 0.607 N
(b) Area of wall,
Let P is the average pressure on that area. It is given by :
P = 0.202 Pa
Hence, this is the required solution.
The frequency f is related to the wavelength 
by the equation
where v is the speed of the wave in the rope.
We can see from the formula that, if v is kept constant, smaller frequency means larger wavelength. So, the rope with frequency 2 Hz will have the longest wavelength.
where v is the speed of the wave in the rope.
We can see from the formula that, if v is kept constant, smaller frequency means larger wavelength. So, the rope with frequency 2 Hz will have the longest wavelength.