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3 years ago

Every year, new records in track and field events are recorded. Let's take a historic look back at some exciting races.

Physics

2 answers:

marissa [1.9K]3 years ago

6 0

Answer: His average speed (in m/s) for the race was 10.08 m/s

Explanation:

Given data

Total distance traveled , D= 100 meter

Total time taken , T= 9.92 seconds

>The average speed( $V_{avg}$ ) of an object is the total distance traveled by the object divided by the total time taken to cover that distance .i.e.,

$V_{avg}=\frac{D}{T}=\frac{100}{9.92}\, \frac{m}{s}=10.08\: \frac{m}{s}$

Thus his average speed (in m/s) for the race was 10.08 m/s

masya89 [10]3 years ago

5 0

V=r/t
Speed equals displacement over the time

V=100/9.92=10.08ms^-1

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