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Olegator [25]
3 years ago
11

Every year, new records in track and field events are recorded. Let's take a historic look back at some exciting races.

Physics
2 answers:
marissa [1.9K]3 years ago
6 0

Answer: His average speed (in m/s) for the race was <u><em>10.08 m/s</em></u>

Explanation:

Given data

Total distance traveled , D= 100 meter

Total time taken , T= 9.92 seconds

>The average speed(V_{avg} ) of an object is the total distance traveled by the object divided by the total time taken to cover that distance .i.e.,

V_{avg}=\frac{D}{T}=\frac{100}{9.92}\, \frac{m}{s}=10.08\: \frac{m}{s}

Thus his average speed (in m/s) for the race was <u><em>10.08 m/s</em></u>

masya89 [10]3 years ago
5 0
V=r/t
Speed equals displacement over the time

V=100/9.92=10.08ms^-1
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Ok i apologise for the messy working but I'll try and explain my attempt at logic

Also note i ignore any air resistance for this.

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Static and kinetic friction example (video) | Khan Academy

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