Y=3x+4.....eq.(i) x+4y=-10....(eq.ii) putting value of y in eq.(ii),we get, x+4(3x+4)=-10 or x+12x+16=-10 or,13x=-10+16 or,13x=6 ●#x=6÷13 putting value if x in eq.(i),we get y=3(6÷13)+4 or,y=18÷13+4 or,y=(18+52)÷13 ●#y=70÷13
Answer:
a. 0.25
b. 0.50
c. 0.75
Step-by-step explanation:
P(E1) = 0.25
P(E2) = 0.25
P(Es) = 0.25
P(E) = 0.25
a. Since there are 4 outcomes with the same probability of occurring, the probability of E occurring is:
b. The probability of any two outcomes occurring is twice the probability of a single outcome occurring
c. The probability of any three outcomes occurring can be written as 100% minus the probability of the remaining outcome occurring
Answer:
Step-by-step explanation:
those are 2 lines, and to graph them find 2 points for each to draw a line trough them
line 1
y-2x=0 so y=2x
pick any value for x
(x=1, y=2*1=2), (x=3, y=2*3=6)
Draw a line trough points (1,2) and (3,6)
line 2
y=4x+3
(x=1, y=4*1+3=7), (x= -1, y= 4(-1)+3= -1)
Draw a line trough points (1,7) and (-1, -1)
Answer:
16.4 TRUST ME
Step-by-step explanation:
Mark as brainliest
