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Hoochie [10]
3 years ago
12

What is mineral called that contains usable amounts of an element

Chemistry
2 answers:
ivolga24 [154]3 years ago
7 0
I'm just guessing
Many oil
castortr0y [4]3 years ago
5 0

Answer: On my test it was ore.

Explanation:

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What does the group number of A elements in the A/B numbering system)
Ivanshal [37]

Answer:

All elements in the same A group will have the same number of

valence electrons.

Explanation:

Group A has 1 valence electrons.

4 0
4 years ago
How many total atoms are in the compound:<br> C6H12O6<br><br> 18<br><br> 6<br><br> 12<br><br> 24
Mice21 [21]
D.) There are 24 atoms in total in that compound.....
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3 years ago
Read 2 more answers
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

from the relation:

number of moles = \frac{mass}{atomic mass of 1 mole}

rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

3 0
3 years ago
A 15.0 L rigid container was charged with 0.5 atm of Krypton gas and 1.5 atm of chlorine gas at 350 C. The krypton and chlorine
Angelina_Jolie [31]

The mass of krypton tetrachloride that can be produced assuming 100% yield is mathematically given as

molar mass=33.29g

<h3>What mass of krypton tetrachloride can be produced assuming 100% yield?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Therefore

n=(0.50)(15.)/0.082*623

n=0.147mol

Hence for clorine

n=0.441mol

Given the reaction

Kr+2cl2---->KrCL4

Hence

molar mass=225.60*0.147

molar mass=33.29g

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brainly.com/question/11231920

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Whewww!! What class is this for
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