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sleet_krkn [62]
3 years ago
13

The most common form of nylon is 63.68% carbon, 9.80% hydrogen, 12.38% nitrogen and 14.14 % oxygen. Calculate the empirical form

ula for nylon.
Chemistry
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

The empirical formule is C6H11NO

Explanation:

Step 1: Data given

Suppose the mass = 100 grams

Nylon contains:

63.68 % carbon = 63.68 grams

9.80 % hydrogen = 9.80 grams

12.38 % nitrogen = 12.38 grams

14.14 % oxygen = 14.14 grams  

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass nitrogen = 14.01 g/mol

Molar mass oxygen = 16.00 g/mol

Step 2: Calculate moles

Moles = mass / moles

Moles C = 63.68 grams / 12.01 g/mol

Moles C = 5.302 moles

Moles H = 9.80 grams / 1.01 g/mol

Moles H = 9.70 moles

Moles N = 12.38 grams / 14.01 g/mol

Moles N = 0.8837 moles

Moles O = 14.14 grams / 16.00 g/mol

Moles O = 0.8838 moles

Step 3: Calculate mol ratio

We divide by the smalleste amount of moles

C: 5.302/0.8837 = 6

H: 9.70/0.8837 = 11

N: 0.8837/0.8837 = 1

O: 0.8838/0.8837 = 1

The empirical formule is C6H11NO

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Answer:

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1. You make like a question or something that you want to investigate, it's like the aim of the experiment.

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A radioisotope decays to give an alpha particle andPb-208.
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<u>Answer:</u> The original element is _{84}^{212}\textrm{Po}

<u>Explanation:</u>

Alpha decay is defined as the process in which alpha particle is emitted. In this process, a heavier nuclei decays into a lighter nuclei. The alpha particle released carries a charge of +2 units.

The released alpha particle is also known as helium nucleus.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

For the given alpha decay process of an isotope:

^{Z}_{A}\textrm{X}\rightarrow ^{208}_{82}\textrm{Pb}+_2^4\alpha

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

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<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

Z = 82 + 2

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The isotopic symbol of unknown element is _{84}^{212}\textrm{Po}

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