Answer:
The empirical formule is C6H11NO
Explanation:
Step 1: Data given
Suppose the mass = 100 grams
Nylon contains:
63.68 % carbon = 63.68 grams
9.80 % hydrogen = 9.80 grams
12.38 % nitrogen = 12.38 grams
14.14 % oxygen = 14.14 grams
Molar mass C = 12.01 g/mol
Molar mass H = 1.01 g/mol
Molar mass nitrogen = 14.01 g/mol
Molar mass oxygen = 16.00 g/mol
Step 2: Calculate moles
Moles = mass / moles
Moles C = 63.68 grams / 12.01 g/mol
Moles C = 5.302 moles
Moles H = 9.80 grams / 1.01 g/mol
Moles H = 9.70 moles
Moles N = 12.38 grams / 14.01 g/mol
Moles N = 0.8837 moles
Moles O = 14.14 grams / 16.00 g/mol
Moles O = 0.8838 moles
Step 3: Calculate mol ratio
We divide by the smalleste amount of moles
C: 5.302/0.8837 = 6
H: 9.70/0.8837 = 11
N: 0.8837/0.8837 = 1
O: 0.8838/0.8837 = 1
The empirical formule is C6H11NO
