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olga_2 [115]
3 years ago
7

At atmospheric pressure a balloon contains 2.00 l of nitrogen gas how would the volume change \

Chemistry
1 answer:
Amanda [17]3 years ago
3 0
The complete question; At atmospheric pressure a balloon contains 2.00 l of nitrogen gas, how would the volume change if the kelvin temperature was only 75 % of its original value? 
 The change in volume would be;
original volume × percentage 
= 2 ×0.75 = 1.5 L
Thus the volume would change by 1.5 L
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why would it not be necessary to heat the air in the balloon as much if the air outside the balloon is colder?
RUDIKE [14]

Hot-air balloons float because the air caught inside the balloon is heated up by a burner, making it less dense than the air outside. As the burner heats the air, it expands and some of the air escapes; that's what makes it less dense

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Heat is being removed from a substance, but its temperature does not change. What is
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4 0
2 years ago
What is the percent of Cr in Cr2O3
IgorLugansk [536]
The percentage of Chromium in Chromium Oxide is calculated as follow,

Step 1:
           Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
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Step 2:
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i.e.
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5 0
3 years ago
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Are atoms the smallest particles we know about, or are there smaller ones?
Schach [20]

Answer:

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Explanation:

7 0
3 years ago
BY ANSWERING THIS QUESTION UR PUTTING IT ON UR MOM's LIFE THAT U WON'T STEAL MY POINTS.
Yakvenalex [24]

Answer:

T_2=-125.58\°C

Explanation:

Hello!

In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:

\frac{T_1}{P_1} =\frac{T_2}{P_2}

Whereas solving for the final temperature T2, we get:

T_2=\frac{T_1P_2}{P_1}

Thus, we plug in the given data (temperature in Kelvins) to obtain:

T_2=\frac{(22+273.15)K*1.75atm}{3.50atm} \\\\T_2=147.58K-273.15\\\\T_2=-125.58\°C

Best regards!

3 0
3 years ago
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