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3 years ago

At atmospheric pressure a balloon contains 2.00 l of nitrogen gas how would the volume change \

1 answer:

3 0

The complete question; At atmospheric pressure a balloon contains 2.00 l of nitrogen gas, how would the volume change if the kelvin temperature was only 75 % of its original value?
The change in volume would be;
original volume × percentage
= 2 ×0.75 = 1.5 L
Thus the volume would change by 1.5 L

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What percentage of oxygen is attributed fossil fuel combustion

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Answer:

C. 4%

Explanation:

The answer is 4%

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2 years ago

Toluene (C6H5CH3 ), an organic compound often used as a solvent in paints, is mixed with a similar organic compound, benzene (C6

Sergeeva-Olga [200]

Explanation:

The given data is as follows.

Weight of solute = 75.8 g, Molecular weight of solute (toulene) = 92.13 g/mol, volume = 200 ml

Therefore, molarity of toulene is calculated as follows.

Molarity = $\frac{\text{weight of solute}}{\text{molecular weight of solute}} \times \frac{1000}{\text{volume of solution in ml}}$

= $\frac{75.8 g}{92.13 g/mol} \times \frac{1000}{200 ml}$

= 4.11 M

Hence, molarity of toulene is 4.11 M.

As molality is the number of moles of solute present in kg of solvent.

So, we will calculate the molality of toulene as follows.

Molality = $\frac{\text{given weight of solute}}{\text{given molecular weight of solute}} \times \frac{1000}{\text{weight of solvent in grams}}$

= $\frac{75.8 g}{92.13 g/mol} \times \frac{1000}{95.6 g}$

= 8.6 m

Hence, molality of given toulene solution is 8.6 m.

Now, calculate the number of moles of toulene as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{75.8 g}{92.13 g/mol}$

= 0.8227 mol

Now, no. of moles of benzene will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{95.6 g}{78.11 g/mol}$

= 1.2239 mol

Hence, the mole fraction of toulene is as follows.

Mole fraction = $\frac{\text{moles of toulene}}{\text{total moles}}$

= $\frac{0.8227 mol}{(0.8227 + 1.2239) mol}$

= 0.402

Hence, mole fraction of toulene is 0.402.

As density of given solution is 0.857 $g/cm^{3}$ so, we will calculate the mass of solution as follows.

Density = $\frac{mass}{volume}$

0.857 $g/cm^{3}$ = $\frac{mass}{200 ml}$ (As 1 $cm^{3}$ = 1 g)

mass = 171.4 g

Therefore, calculate the mass percent of toulene as follows.

Mass % = $\frac{\text{mass of solute}}{\text{mass of solution}} \times 100$

= $\frac{75.8 g}{171.4 g} \times 100$

= 44.22%

Therefore, mass percent of toulene is 44.22%.

8 0

4 years ago

How to answer this ?

nadezda [96]

You multiply (4×10)by*

6 0

3 years ago

2) Nitrogen gas will react with hydrogen gas to produce ammonia, NH3, How many

Delicious77 [7]

Answer:

12 grams of hydrogen gas

and 56 grams of nitrogen gas

The molar mass of ammonia is 17 g/mol.

68 grams of ammonia corresponds to

17g/mol

68g

=4moles

4 moles of ammonia will be obtained from

4×1

=2 moles of nitrogen and

4×3

=6 moles of hydrogen.

The molar masses of nitrogen and hydrogen are 28 g/mol and 2 g/mol respectively.

2 moles of nitrogen corresponds to 2×28=56 grams.

6 moles of hydrogen corresponds to 6×2=12 grams.

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2 years ago

The density of a liquid is 1.28 g/mL. What is the volume of a 32.4 g sample of this liquid in mL units?

alex41 [277]

The answer is 25.3125mL

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3 years ago