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Doss [256]
2 years ago
5

Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes formula hydroch

loric acid hcl sodium hydroxide naoh formic acid hcooh methyl amine ch3nh2 potassium chloride kcl ethanol c2h5oh sucrose c12h22o11
Chemistry
1 answer:
matrenka [14]2 years ago
3 0

Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.


Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.

  • Hydrochloric acid, HCl

On adding HCl (strong acid) in water, it will completely dissociates into ions (H^{+} and Cl^{-}) and thus, it is a strong electrolyte.

  • Sodium hydroxide, NaOH

On adding NaOH (strong base) in water, it will completely dissociates into ions (Na^{+} and  OH^{-}) and thus, it is a strong electrolyte.

  • Formic acid, HCOOH

On adding HCOOH (weak acid) in water, it will partially dissociates into ions (H^{+} and  HCOO^{-}) and thus, it is a weak electrolyte.

  • Methyl amine, CH_3NH_2

On adding CH_3NH_2 (weak base) in water, it will partially dissociates into ions (CH_3NH_3^{+} and  OH^{-}) and thus, it is a weak electrolyte.

  • Potassium chloride, KCl

On adding KCl in water, it will completely dissociates into ions (K^{+} and  Cl^{-}) and thus, it is a strong electrolyte.

  • Ethanol, C_2H_5OH

On adding C_2H_5OH in water, it will not dissociates into ions  and thus, it is a nonelectrolyte.

  • Sucrose, C_{12}H_{22}O_{11}

On adding C_{12}H_{22}O_{11} in water, it will not dissociates into ions  and thus, it is a nonelectrolyte.

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3 years ago
Sugar when dissolved into water, propose whether the compound forms atoms, molecules or lattices. Justify you answer
kirza4 [7]

Answer:

atoms

Explanation:

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6 0
3 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
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Answer:

B - To increase the rate of the reaction

Explanation:

Catalysts speed up the reaction without being reactants or products, so aren't used up in the reaction.

6 0
2 years ago
The electron pair in a C-F bond could be considered Question 3 options: closer to C because carbon has a larger radius and thus
Leokris [45]

Answer:

closer to F because fluorine has a higher electronegativity than carbon

Explanation:

Electronegativity refers to the ability of an atom in a bonding situation to draw the shared electrons of the bond closer to itself.

Electronegativity increases across the period and decreases down the group. A highly electronegative atom draws the shared electron pair of a bond towards itself.

When two atoms are bonded together, the electron pair is always drawn closer to the atom that has a higher electronegativity.

Hence, the electron pair in a C-F bond could be considered closer to F because fluorine has a higher electronegativity than carbon.

4 0
2 years ago
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