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algol [13]
3 years ago
14

Which of the following atoms releases more energy than oxygen when an electron is added to its valence energy level?

Chemistry
1 answer:
Rus_ich [418]3 years ago
5 0
The answer is b. fluorine (F). This is because fluorine is a more electronegative (electron loving) atom compared to oxygen. It is found on the 7th group of the periodic table, so it has 7 valence electrons. It only needs one more electron to achieve the ideal number of valence electrons which is 8. Oxygen, on the other hand, is in group 6 so it needs 2 more electrons to complete its valency. Helium can't be the answer because it is already in group 8, meaning it is already stable and won't release energy.
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factors that affect the rate of a chemical reaction include which of the following? i. frequency of collisions of reactant parti
pickupchik [31]
I, ii is the answer
7 0
2 years ago
Round to the nearest whole number of 99.59
Luden [163]
Answer is 100.00!!!
8 0
3 years ago
2. To what volume will you have to dilute 20.0 ml of a 8 M HCl solution to make a 0.35 M
GrogVix [38]

Answer:

You need to dilute 8 M HCl to 0.35 M to make 457 mL.

Explanation:

Use the equation M₁V₁=M₂V₂

Convert the mL to L : 20 mL= 0.02 L

8 M x 0.02 L = 0.35 M x V₂

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3 0
3 years ago
Balance Fe3O4 + H2 = Fe + H2O
Snezhnost [94]
Fe3O4 + 4H2 = 3Fe + 4H2O

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3 0
3 years ago
What is the ph of a solution of 1.699 l of 1.25 m hcn, ka = 6.2 x 10-10, and 1.37 moles of nacn?
BlackZzzverrR [31]

The pH of a solution is 9.02.

c(HCN) = 1.25 M; concentration of the cyanide acid

n(NaCN) = 1.37 mol; amount of the salt

V = 1.699 l; volume of the solution

c(NaCN) = 1.37 mol ÷ 1.699 l

c(NaCN) = 0.806 M; concentration of the salt

Ka = 6.2 × 10⁻¹⁰; acid constant

pKa = -logKa

pKa = - log (6.2 × 10⁻¹⁰)

pKa = 9.21

Henderson–Hasselbalch equation for the buffer solution:

pH = pKa + log(cs/ck)

pH = pKa + log(cs/ck)

pH = 9.21 + log (0.806M/1.25M)

pH = 9.21 - 0.19

pH = 9.02; potential of hydrogen

More about buffer: brainly.com/question/4177791

#SPJ4

8 0
1 year ago
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