Answer:
Atomic radius of Strontium is 27.38pm
Explanation:
In a face-centered cubic structure, the edge, a, could be obtained using pythagoras theorem knowing the hypotenuse of the unit cell, b, is equal to 4r:
a² + a² = b² = (4r)²
2a² = 16r²
a = √8 r
As edge length of Strontium is 77.43pm:
77.43pm / √8 = r
27.38pm = r
<h3>Atomic radius of Strontium is 27.38pm</h3>
Answer:
Option A. 9.4 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 8 L
Initial temperature (T₁) = 293 K
Final temperature (T₂) = 343 K
Final volume (V₂) =?
V₁ / T₁ = V₂ / T₂
8 / 293 = V₂ / 343
Cross multiply
293 × V₂ = 8 × 343
293 × V₂ = 2744
Divide both side by 293
V₂ = 2744 / 293
V₂ = 9.4 L
Therefore, the final volume of the gas is 9.4 L
Answer:
1)Krypton
2)11H
Explanation:
electrons=protons
protons=atomic number
mass number=protons+neutrons
mass number is the superscript
atomic number is the subscript.
1)The answer is Krypton because its atomic number= number of protons=number of electrons is 36.
mass number is 46+36=82.
2)subscript=atomic number=number of protons=number of electrons
i. H = electrons=1
=neutrons=0
ii. Cl=electrons=17
=neutrons=35-17=18
iii. Na=electrons=11
=neutrons=23-11= 12
so the answer is Hydrogen because it has 1 electron and 0 neutron.
I hope this helps.
Answer:
The endpoint volume is 50.52 ± 0.14 mL
Explanation:
In a titration always is necessary to subtract the blank volume to the titrant volume to obtain the real volume of the titrant. Thus in this case, the total endpoint volume is the sum of the initial volume delivered and the second volume delivered, minus the blank volume:
V = (49.16±0.06 mL) + (1.69±0.04 mL) - (0.33±0.04 mL)
V = (49.16 + 1.69 - 0.33) ± (0.06+0.04+0.04) mL
V = 50.52 ± 0.14 mL
It is necessary to consider the sum of the errors too.
