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Alex73 [517]
3 years ago
15

Classify each of the following elements as

Chemistry
2 answers:
sweet [91]3 years ago
6 0

The non-metals are boron and carbon. The metal is aluminum and the metalloid is silicon.

Explanation:

non-metal = boron, carbon

metal = aluminum

metalloid = silicon

tino4ka555 [31]3 years ago
5 0

Answer:Silicon is neither metal nor non-metal; it's a metalloid, an element that falls somewhere between the two. The category of metalloid is something of a gray area, with no firm definition of what fits the bill, but metalloids generally have properties of both metals and non-metals.

Explanation:

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A certain ore is 24.3% nickel by mass. how many kilograms of this ore would you need to dig up to have 55.0 g of nickel?
zysi [14]
Let x be the mass of the ore in grams such that the equation that would allow us to answer this item would be,

                     55 = (x)(0.243)

The value of x is calculated as,

                 x = 55/0.243
                   x = 226.337 grams

Then, solve for amount in kilograms by dividing the calculated value by 1000. This methodology will give us an answer of 0.226337. Hence, the answer is 0.226. 


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3 years ago
Which of the following questions is a scientific question?
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Explanation:

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3 years ago
Which group on the periodic table contains chemical elements that are shiny and conduct electricity?
olga_2 [115]
D. Metals
Elements that are shiny, solid, conducts electricity, has atomic mass of 108 is metal.
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PLS HELP Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement
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3 0
3 years ago
A 2.00 L sample of gas at 35C is to be heated at constant pressure until it reaches a volume of 5.25 L. To what Kelvin temperatu
Anastaziya [24]

Answer:

The sample will be heated to 808.5 Kelvin

Explanation:

Step 1: Data given

Volume before heating = 2.00L

Temperature before heating = 35.0°C = 308 K

Volume after heating = 5.25 L

Pressure is constant

Step 2: Calculate temperature

V1 / T1 = V2 /T2

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⇒ T1 = the initial temperature = 308 K

⇒ V2 = the final volume = 5.25 L

⇒ T2 = The final temperature = TO BE DETERMINED

2.00L / 308.0 = 5.25L / T2

T2 = 5.25/(2.00/308.0)

T2 = 808.5 K

The sample will be heated to 808.5 Kelvin

7 0
4 years ago
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