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3 years ago

Light behaves as a longitudinal wave

Chemistry

2 answers:

garik1379 [7]3 years ago

5 0

More information??? Confused

andre [41]3 years ago

3 0

Answer:

No, light behaves as a Transverse Wave. All electromagnetic waves behave as transverse waves.

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Why is very important to wait until the crucible is fully coleed to room temperature before weighting

Mars2501 [29]

If you do not wait until the crucible is at room temperature, its density will vary constantly until it reaches this temperature, since density is a property that varies with temperature. For the above reason, weighing a hot crucible will not allow the measurement of a constant weight on the balance, since <u>the weight of the object will be constantly changing, which will not allow a constant reading.</u>

3 0

3 years ago

What does the symbol H stand for

muminat

Answer:

enthalpy

Explanation:

If it is used with a triangle in front, (delta H), that means the change in enthalpy. Delta H= (m)(s)(Delta T). m=mass of products, s=heat of the products, Delta T = change in temperature.

Hope that helps

4 0

3 years ago

A certain FM radio wave has a frequency of 1.31 x 108 Hz. Given that radio waves travel at

Westkost [7]

Answer:

2.28 m

Explanation:

Use the relationship

λ=vf

to solve for wavelength λ. Substituting the known quantities yields:

λ=vf

λ=2.99 x 108 m/s1.31 x 108 Hz

λ=2.28 m

4 0

3 years ago

An example of a physical property of an element is the element’s ability to(1) react with an acid(2) react with oxygen(3) form a

Thepotemich [5.8K]

<span>4: Form An Aqueous Solution

This is the only answer that can be observed without testing gear and with the naked eye.... Hope I helped ^-^</span>

5 0

3 years ago

Read 2 more answers

Nicotine, a component of tobacco, is composed of C, H, and N. A 7.875-mg sample of nicotine was combusted, producing 21.363 mg o

Gnom [1K]

Answer: The empirical formula for the given compound is $C_5H_7N$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, and nitrogen follows:

$C_xH_yN_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and nitrogen respectively.

We are given:

Mass of $CO_2=21.363mg=21.363\times 10^3g=21363g$

Mass of $H_2O=6.125g=6.125\times 10^3g=6125g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 21363 g of carbon dioxide, $\frac{12}{44}\times 21363=5826.27g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 6125 g of water, $\frac{2}{18}\times 6125=680.55$ of hydrogen will be contained.

Now we have to calculate the mass of nitrogen.

Mass of nitrogen in the compound = (7875) - (5826.27 + 680.55) = 1368.18 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5826.27g}{12g/mole}=485.52moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{680.55g}{1g/mole}=680.55moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{1368.18g}{14g/mole}=97.73moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0154 moles.

For Carbon = $\frac{485.52}{97.73}=4.96\approx 5$

For Hydrogen = $\frac{680.55}{97.73}=6.96\approx 7$

For Nitrogen = $\frac{97.73}{97.73}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 5 : 7 : 1

Hence, the empirical formula for the given compound nicotine is $C_5H_7N_1=C_5H_7N$

7 0

3 years ago