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sergij07 [2.7K]
3 years ago
12

A toy rocket is shot straight up into the air with an initial speed of 45.0 m/s how long does it takes for the rocket to reach i

t's highest point ?
Physics
2 answers:
baherus [9]3 years ago
5 0

Explanation:

Given that,

Initial speed of the toy rocket, u = 45 m/s

Let t is the time taken by the rocket  to reach it's highest point. At the highest point the final speed of the rocket is 0. Using equation of kinematics to find the value of t as :

v=u+at

u=-at

Here, a = -g

t=\dfrac{u}{a}

t=\dfrac{45}{9.8}

t = 4.59 seconds

So, the rocket will take 4.59 seconds to reach its highest point. Hence, this is the required solution.

Serjik [45]3 years ago
3 0
It will be
45/9.8 = t
4.6 sec
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(a) The unknown charge kept at distance 0.250m directly below  -0.450 charge is  2.315 x 10⁻¹² C.

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The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

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Given is a negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it .

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Substituting the values into the expression ,we get the charge

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Learn more about electrostatic force.

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