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mina [271]
3 years ago
8

Why do nonmetals tend to gain electrons to form negative ions?

Chemistry
1 answer:
kompoz [17]3 years ago
8 0

Answer:

they gain the few electrons they need to form full octets

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Calcium carbide, CaC2, is manufactured by reducing lime with carbon at high temperature. (The carbide is used in turn to make ac
sweet-ann [11.9K]

The energy of the carbide released is 7262.5MJ.

<h3>What is the energy?</h3>

We know that the reaction between calcium  oxide and carbon occurs in accordance with the reaction; CaO(s)+3C(s)----- > CaC_{2} (s)+CO(g). The reaction is seen to produce 464.8kJ of energy per mole of carbide produced.

Number of moles of CaC_{2} produced = 1000 * 10^3 g/64 g/mol

= 15625 moles of calcium carbide

If 1 mole of CaC_{2} transfers  464.8 * 10^3 J

15625 moles of calcium carbide transfers 15625 moles  * 464.8 * 10^3 J/ 1 mol

= 7262.5MJ

Learn more about reaction enthalpy:brainly.com/question/1657608

#SPJ1

7 0
2 years ago
Which is a way you would expect two animals of the same species to differ?
LuckyWell [14K]
C is the correct answer
5 0
3 years ago
How many 3-liter balloons could the 12-L helium tank pressurized to 160 atm fill? Keep in mind that an "exhausted" helium tank i
vaieri [72.5K]

Answer:

The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons

Explanation:

It is possible to answer this question using Boyle's law:

P_1V_1=P_2V_2

Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:

160atm×12L = 1atm×V₂

V₂ = 1920L

As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:

1920L - 12L = 1908L

1908L will fill:

1908L×\frac{1balloon}{3L} = <em>636 balloons</em>

<em></em>

I hope it helps!

7 0
4 years ago
Describe how this instrument works.<br><br> Operation:
blsea [12.9K]

Answ

Explanation:

that is like a satelite it helps detect signals from like outer space and things

4 0
3 years ago
Read 2 more answers
If the cylindrical pistons are 25.000 cm in diameter at 20.0 ∘c, what should be the minimum diameter of the cylinders at that te
attashe74 [19]
Refer to the diagram shown below.

The piston supports the same load W at both temperatures.
The ideal gas law is
pV=nRT
where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant

State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter

State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter

Because V, n, and R remain the same between the two temperatures, therefore
\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}

If the supported load is W kg, then
p_{1} =  \frac{W \, N}{ \frac{\pi}{4} d_{1}^{2}} = \frac{4W \, N}{\pi (0.25 \, m)^{2}} =  20.3718W \, Pa
Similarly,
p_{2} =  \frac{4W}{\pi d_{2}^{2}} \, Pa

\frac{p_{1}}{p_{2}} =  \frac{20.3718 \pi d_{2}^{2}}{4} = 16 d_{2}^{2}

Because p₁/p₂ = T₁/T₂, therefore
16d_{2}^{2} =  \frac{293}{423}  \\\\ d_{2}^{2} =  \frac{0.6927}{16}  \\\\ d_{2} = 0.2081 \, m

The minimum piston diameter at 150 C is 20.8 cm.

Answer: 20.8 cm diameter

8 0
4 years ago
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