Question

Calcium carbide, CaC2, is manufactured by reducing lime with carbon at high temperature. (The carbide is used in turn to make acetylene, an industrially important organic chemical.) CaO(s)+3C(s)→CaC2(s)+CO(g) ΔH=464.8kJ Calculate the quantity of energy, in MJ, transferred when a metric ton(1000 kg) of CaC2(s) is manufactured. Ca = 40 g/mol C = 12 g/mol O = 16 g/mol

Answer 1

The energy of the carbide released is 7262.5MJ.

What is the energy?

We know that the reaction between calcium  oxide and carbon occurs in accordance with the reaction; $CaO(s)+3C(s)----- > CaC_{2} (s)+CO(g)$. The reaction is seen to produce 464.8kJ of energy per mole of carbide produced.

Number of moles of $CaC_{2}$ produced = 1000 * 10^3 g/64 g/mol

= 15625 moles of calcium carbide

If 1 mole of $CaC_{2}$ transfers  464.8 * 10^3 J

15625 moles of calcium carbide transfers 15625 moles  * 464.8 * 10^3 J/ 1 mol

= 7262.5MJ

Learn more about reaction enthalpy:brainly.com/question/1657608

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