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aivan3 [116]
1 year ago
12

Calcium carbide, CaC2, is manufactured by reducing lime with carbon at high temperature. (The carbide is used in turn to make ac

etylene, an industrially important organic chemical.) CaO(s)+3C(s)→CaC2(s)+CO(g) ΔH=464.8kJ Calculate the quantity of energy, in MJ, transferred when a metric ton(1000 kg) of CaC2(s) is manufactured. Ca = 40 g/mol C = 12 g/mol O = 16 g/mol
Chemistry
1 answer:
sweet-ann [11.9K]1 year ago
7 0

The energy of the carbide released is 7262.5MJ.

<h3>What is the energy?</h3>

We know that the reaction between calcium  oxide and carbon occurs in accordance with the reaction; CaO(s)+3C(s)----- > CaC_{2} (s)+CO(g). The reaction is seen to produce 464.8kJ of energy per mole of carbide produced.

Number of moles of CaC_{2} produced = 1000 * 10^3 g/64 g/mol

= 15625 moles of calcium carbide

If 1 mole of CaC_{2} transfers  464.8 * 10^3 J

15625 moles of calcium carbide transfers 15625 moles  * 464.8 * 10^3 J/ 1 mol

= 7262.5MJ

Learn more about reaction enthalpy:brainly.com/question/1657608

#SPJ1

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If kc = 7.04 × 10-2 for the reaction: 2 hbr(g) ⇌h2(g) + br2(g), what is the value of kc for the reaction: 1/2 h2(g) + 1/2 br2 ⇌h
Kay [80]
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7.04X10^-2 = [H2][Br] / [HBr]^2

at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root: 
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769 
7 0
3 years ago
Zinc blende, or sphalerite, can be described as having a face-centered cubic unit cell with sulfur atoms at each lattice point a
g100num [7]

Answer:

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7 0
3 years ago
a strip of impure copper is given to you. how will you purify it by using chemical effects of electric current ?
Oksi-84 [34.3K]

This can be done through electrolysis. Electrolysis is the separation of a substance  into two or more substances that may differ from each other and from the original substance by passing an electric current through a solution that contains ions.

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When the electric current is switched on, the bar of pure copper which is the cathode  increases greatly in size as copper ions leave the anode of impure copper and attach to  the cathode.  The anode becomes smaller and smaller as it loses copper ions until all that is left of it is impurities in form of a sludge beneath it.


6 0
3 years ago
Read 2 more answers
How much energy (in Joules) would it take to warm 3.11 grams of gold by 7.7 oC
Reptile [31]

Answer:

It would take 3.11 J to warm 3.11 grams of gold

Explanation:

Step 1: Data given

Mass of gold = 3.11 grams

Temperature rise = 7.7 °C

Specific heat capacity of gold = 0.130 J/g°C

Step 2: Calculate the amount of energy

Q = m*c*ΔT

⇒ Q = the energy required (in Joules) = TO BE DETERMINED

⇒ m = the mass of gold = 3.11 grams

⇒ c = the specific heat of gold = 0.130 J/g°C

⇒ ΔT = The temperature rise = 7.7 °C

Q = 3.11 g * 0.130 J/g°C * 7.7 °C

Q = 3.11 J

It would take 3.11 J to warm 3.11 grams of gold

4 0
3 years ago
Which best explains why blood is considered to be a suspension?
Stells [14]
I think the best answer is b): it contains particles that can settle out.

The definition of suspension is a heterogeneous (that is same in all parts) mixture that contains particles that could undergo sedimentation (settle down) - this definition is close to b). It should not matter whether those particles are nutrients( so A or C are not good answers).


5 0
3 years ago
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