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Rainbow [258]
3 years ago
6

A solution is prepared by mixing the 50 mL of 1 M NaH2PO4 with 50 mL of 1 M Na2HPO4. On the basis of the information, which of t

he following species is present in the solution at the lowest concentration?Extra ContentH3PO4 <--> H+ + H2PO4- Ka1 = 7.2 E-3H2PO4- <--> H+ + HPO42- Ka2 = 6.3 E-8HPO42- <--> H+ + PO43- Ka3 = 4.5 E-13answer options:A. PO43-B. H2PO4-C. HPO42-D. Na+
Chemistry
1 answer:
barxatty [35]3 years ago
4 0

Answer:

A. PO43-

Explanation:

in the given is buffer . so H2PO4- and HPO42- both are present with equal concentration . Na+ is spectator ion it is also present in the concentration higher than the given species above .

but PO4-3 is not present . so it is lowest concentration

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The polarity of a bond between two elements can be best determined by difference in the values of electronegativity.

<h3>Determination of polarity of bond</h3>

The polarity of a covalent bond can be determined by determining the difference in electronegativity between the two bonded atoms. Electronegativity is defined as the tendency of an atom to attract electrons to itself.

So we can conclude that the polarity of a bond between two elements can be best determined by difference in the values of electronegativity.

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7 0
2 years ago
How many molecules are in 68.0 g of H2S
Kryger [21]

The correct answer is 12.044 × 10²³ molecules.  

The molecular mass of H₂S is 34 gram per mole.  

Number of moles is determined by using the formula,  

Number of moles = mass/molecular mass

Given mass is 68 grams, so no of moles will be,  

68/34 = 2 moles

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= 12.044 × 10²³ molecules.  


3 0
3 years ago
Salinity is a measure of which of the following in water?
Lemur [1.5K]
The answer is dissolved salts
8 0
3 years ago
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Determine the percent water in MgSO4*7H20?
Semmy [17]

Answer:

\% H_2O=51.2\%

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol

Thus, the percent water is:

\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\

So we plug in to obtain:

\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%

Best regards!

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Answer:

Explanation:

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2 years ago
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