A solution is prepared by mixing the 50 mL of 1 M NaH2PO4 with 50 mL of 1 M Na2HPO4. On the basis of the information, which of t

Question

3 years ago

6

A solution is prepared by mixing the 50 mL of 1 M NaH2PO4 with 50 mL of 1 M Na2HPO4. On the basis of the information, which of t

he following species is present in the solution at the lowest concentration?Extra ContentH3PO4 <--> H+ + H2PO4- Ka1 = 7.2 E-3H2PO4- <--> H+ + HPO42- Ka2 = 6.3 E-8HPO42- <--> H+ + PO43- Ka3 = 4.5 E-13answer options:A. PO43-B. H2PO4-C. HPO42-D. Na+

Chemistry

1 answer:

barxatty [35] · Answer 1 · 2021-11-26T16:57:19+03:00

barxatty [35]3 years ago

4 0

Answer:

A. PO43-

Explanation:

in the given is buffer . so H2PO4- and HPO42- both are present with equal concentration . Na+ is spectator ion it is also present in the concentration higher than the given species above .

but PO4-3 is not present . so it is lowest concentration