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Vadim26 [7]
3 years ago
14

H2PO4-(aq) ⇆ H+(aq) + HPO42-( which ion plays the role of hydrogen ion donor and which one plays the hydrogen ion acceptor in BP

S?
Chemistry
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

<u>H2PO4- is a proton donor and HPO42_ is a proton acceptor</u>

Explanation:

Step 1: What are hydrogen ion donor and acceptor

in the following reaction we see that:

⇒ H2PO4- is more likely to give a H+ ion to form HPO42-.  

⇒HPO42- is more likely to take a H+ ion, to form H2PO4-

The reaction of an acid in water solvent is described as a dissociation :

HA ⇔ H+ + A-

⇒where HA is a proton acid

So, H2PO4- = HA   and  HPO42- = A-

Acids are proton donors. So, <u>H2PO4- is a proton donor and HPO42_ is a proton acceptor</u>

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\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3

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Hess's Law of Constant Heat Summation states that if a chemical equation can be written as the sum of several other chemical equations, the enthalpy change of the first chemical equation is equal to the sum of the enthalpy changes of the other chemical equations. Thus, the reaction that involves the conversion of reactant A to B, for example, has the same enthalpy change even if you convert A to C, before converting it to B. Regardless of how many steps it takes for the reactant to be converted to the product, the enthalpy change of the overall reaction is constant.

With Hess's Law in mind, let's see how A can be converted to 2C +E.

\bf{\text{A} \rightarrow 2\text{B}}                  (Δ\text{H}_1)  -----(1)

Since we have 2B, multiply the whole of II. by 2:

\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}       (2Δ\text{H}_2) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is \text{A} \rightarrow 2\text{C} +2\text{D}.

Reversing III. gives us a negative enthalpy change as such:

\bf{2\text{D} \rightarrow \text{E}}                  (-Δ\text{H}_3) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of \text{A} \rightarrow 2\text{C} +\text{E}, which is also the equation of interest.

Adding all three together:

\text{A} \rightarrow 2\text{C}+\text{E}            (\bf{\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3 })

Thus, the first option is the correct answer.

Supplementary:

To learn more about Hess's Law, do check out: brainly.com/question/26491956

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