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Vadim26 [7]
3 years ago
14

H2PO4-(aq) ⇆ H+(aq) + HPO42-( which ion plays the role of hydrogen ion donor and which one plays the hydrogen ion acceptor in BP

S?
Chemistry
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

<u>H2PO4- is a proton donor and HPO42_ is a proton acceptor</u>

Explanation:

Step 1: What are hydrogen ion donor and acceptor

in the following reaction we see that:

⇒ H2PO4- is more likely to give a H+ ion to form HPO42-.  

⇒HPO42- is more likely to take a H+ ion, to form H2PO4-

The reaction of an acid in water solvent is described as a dissociation :

HA ⇔ H+ + A-

⇒where HA is a proton acid

So, H2PO4- = HA   and  HPO42- = A-

Acids are proton donors. So, <u>H2PO4- is a proton donor and HPO42_ is a proton acceptor</u>

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  Mathematically;

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Preventive maintenance on a hot water heater includes:
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Which of the following best represents the reaction between sulfuric acid and calcium hydroxide? f H2SO4 + 2Ca(OH)2 → 2CaSO4 + 3
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Answer:

g. H₂SO₄ + Ca(OH)₂ → CaSO₄ + 2H₂O.

Explanation:

Sulfuric acid is represented as H₂SO₄ and calcium hydroxide is represented as Ca(OH)₂.

  • To balance a chemical reaction. we should apply the law of conservation of mass that the no. of different atoms in both sides (reactants and products).

  • The only choice that represent the reactants correctly and apply the law of conversation of mass is:

<em>g. H₂SO₄ + Ca(OH)₂ → CaSO₄ + 2H₂O.</em>

<em></em>

<em>f. H₂SO₄ + 2Ca(OH)₂ → 2CaSO₄ + 3H₂O </em>

is not correct that the no. of S, and O is not equal in both reaction sides.

S in reactants (1) while in products (2).

<em>O in reactants (8) while in products (11).</em>

<em></em>

<em>h. HSO₄ + CaOH → CaSO₄ + H₂O</em>

The reactants is represented in a wrong way.

<em> j. H₂SO₄+ Ca(OH)₂ → CaSO₄ + H₂O</em>

is not correct that the no. of H and O is not equal in both reaction sides.

H in reactants (4) while in products (2).

O in reactants (6) while in products (5).

<em></em>

<em>So, the right choice is: g. H₂SO₄ + Ca(OH)₂ → CaSO₄ + 2H₂O.</em>

<em></em>

5 0
3 years ago
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