Please helpWhat is the possible ions of vanadium?
1 answer:
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For this reaction to proceed, the following bond breaking should occur:
*one C-O bond* one H-Cl bond
After, the following bond formations should occur:*one C-Cl bond*one O-H bond
Now, add the bond energies for the respective bond energies which can be found in the attached picture. For bond formations, energy is negative. For bond breaking, energy is positive.
ΔHrxn = (1)(358) + (1)(431) + 1(-328) + 1(-463) =<em> -2 kJ</em>
*one C-O bond* one H-Cl bond
After, the following bond formations should occur:*one C-Cl bond*one O-H bond
Now, add the bond energies for the respective bond energies which can be found in the attached picture. For bond formations, energy is negative. For bond breaking, energy is positive.
ΔHrxn = (1)(358) + (1)(431) + 1(-328) + 1(-463) =<em> -2 kJ</em>