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dsp73
3 years ago
15

Can something have energy without having momentum? explain. can something have momentum without having energy? defend your answe

r
Physics
1 answer:
marta [7]3 years ago
8 0
Momentum  is a product mass and velocity. If a certain object posses a kinetic energy, then it should have a momentum since it is moving which has a velocity. However, if the object is at rest and only has potential energy, then it would not have momentum. So, for the first question the answer would be yes, an object can have energy without having any momentum. For the second question, every object whether it is moving or at rest, possess some energy, potential for an object at rest and kinetic for an object that is moving. Thus, the answer would be no, an object having momentum would always have energy.
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The momentum of an object depends on what two forces
mr_godi [17]

The Linear momentum depends on

1) Mass

2) Linear Velocity

The angular momentum depends on

1) Inertia

2) Rotational velocity

7 0
3 years ago
A heavy frog and a light frog jump straight up into the air. They push off in such away that they both have the same kinetic ene
Ilia_Sergeevich [38]

Answer:

The lighter frog goes higher than the heavier frog.

The lighter frog is moving faster than the heavier frog

Explanation:

If both frogs have the same kinetic energy when they leave the ground, the following equality applies:

K(light) = K(heavy) = \frac{1}{2} *ml*vol^{2} = \frac{1}{2}*mh*voh^{2}

Now, if the only force acting on the frogs is gravity, when they reach to the maximum height, we can apply the following kinematic equation:

vf^{2} -vo^{2} = 2*a*hmax = vf^{2} -vo^{2} = 2*(-g)*hmax

When h= hmax, the object comes momentarily to an stop, so vf =0

Solving for hmax:

hmax =\frac{vo^{2} }{2*g}

As the lighter frog, in order to have the same kinetic energy than the heavier one, has a greater initial velocity, it will go higher than the other.

As a consequence of both having the same kinetic energy, the lighter frog will be moving faster than the heavier frog.

5 0
3 years ago
A student with a mass of 65.5 kg runs up a flight of 18 stairs. Each of the steps has a height of 16.5 cm. The student was able
Helga [31]

The power developed by the student is 756.9 J/s and remains the same if the student takes the same time to climb the stairs when climbing it in two's and three's.

<h3>What is power?</h3>

Power is the rate at work is done.

  • Power = work done/time
  • work done = mass × acceleration due to gravity × height

Work done = 65.5 × 10 × (18 × 0.165) = 1945.35 J

Power = 1945.35/2.57 = 756.9 J/s

If the student climbed the steps in two or three at a time, the power does not change if the time remains the same.

  • Time required = Energy/ power

The time required to convert the Big Mac meal from McDonalds = 4 853 440/756.9

Time required = 6412.26 seconds

Therefore, from the power developed by the student, it will take him 6412.26 seconds to convert all the energy in a Big Mac meal.

Learn more about power at: brainly.com/question/1634438

#SPJ1

5 0
2 years ago
Determine the average velocity and average speed for the following situation. A dog runs west for 35 meters then turns east for
mart [117]

Answer:

0.882 m/s average velocity and 1.71 m/s average speed

Explanation:

The dog travels a total of 35 m west and 110 m east.

110-35 = 75 m east of the starting position. Since velocity is a vector you must consider its first and final position and not the total distance traveled.

75 m / 85 s = 0.882 m/s average velocity

Speed is not concerned with direction so we instead add the total distance traveled which is 35+110 = 145 m. We then perform the same operation as before and divide by the time it took to run this distance.

145 m / 85 s = 1.71 m/s average speed

7 0
3 years ago
A 2cm length of wire centered on the origin carries a 20A current directed in the positive y direction. Determine the magnetic f
skad [1K]

Answer:

The magnetic field at a distance x = 5 m is 1.59 nT

Explanation:

Length of the wire, L = 2 cm = 0.02 m

Current, I = 20 A

x = 5 m

Magnetic field at a distance x = 5 m due to an infinitely long wire is given by:

B = \frac{\mu_{o}IL}{4\pi x\sqrt{x^{2} + L^{2}}}

B = \frac{4\pi\times 10^{- 7}\times 20\times 0.02}{4\pi \times 5\sqrt{5^{2} + 0.02^{2}}} = 1.59\times 10^{- 9}\ T

3 0
3 years ago
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