Vf = vi + at
0m/s = 40m/s + a(0.025s)
a = -1600m/s^2
Fnet = ma
Fnet = (0.10kg)(-1600m/s^2)
Fnet = -160 N
hope that helps
Answer:
0.0192A
Explanation:
Since, the reading of the galvanometer is 0 A, the voltage across the resistance R will be:
Step 1
VR = V2
VR = 3.00v
Step 2
Calculating the current through the resistance R as below,
IR = V1 - V2 /R1
IR = 12 - 3 /468
IR =0.0192A
Answer: Individuals with high self efficacy will participate readily and more frequently, will put more effort in and persist longer, enhancing performance in sport and exercise
Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.