We have the relation
where 
denotes the velocity of a body A relative to another body B; here I use B for boat, E for Earth, and R for river.
We're given speeds
Let's assume the river flows South-to-North, so that
and let 
be the angle made by the boat relative to East (i.e. -90° corresponds to due South, 0° to due East, and +90° to due North), so that
Then the velocity of the boat relative to the Earth is
The crossing is 153.0 m wide, so that for some time 
we have
which is minimized when 
so the crossing takes the minimum 30.0 s when the boat is pointing due East.
It follows that
The boat's position 
at time is
so that after 30.0 s, the boat's final position on the other side of the river is
and the boat would have traveled a total distance of
Answer:
because it is less dense than the surrounding air
Explanation:
The work that is done when twice the load is lifted twice the distance is
four times as much
The net work performed by forces acting on an object equals the change in kinetic energy, according to the work-energy theorem.
when an item slows down, the net work applied to it decreases, its change in kinetic energy is negative, and its ultimate kinetic energy is less than its starting kinetic energy. When an item accelerates, positive net work is done on it. All the forces acting on an item must be taken into consideration when determining the net work. You will obtain an incorrect result if you exclude any forces that affect an item or if you add any forces that do not affect it.
Hence The work that is done when twice the load is lifted twice the distance is four times as much
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Answer:
200 mL
Explanation:
Given that,
Initial volume, V₁ = 300 mL
Initial pressure, P₁ = 0.5 kPa
Final pressure, P₂ = 0.75 kPa
We need to find the final volume of the sample if pressure is increased at constant temperature. It is based on Boyle's law. Its mathematical form is given by :
V₂ is the final volume
So, the final volume of the sample is 200 mL.
