Ignoring air resistance . . .
After the bomb is released, tangential (horizontal) acceleration is zero,, normal (vertical) acceleration is 9.8 m/s^2 down (gravity).
I think what’s wrong is that the paper clip isn’t connecting to the other thing on the bottom
During the parts in the orbit where the moon is farthest away from the earth the tides will be low. Whereas during the parts where the moon is closer to the earth the tides will be higher.
Good Luck!
Please correct me if i'm wrong
To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,

Here,
m = Order of the fringes
D = Distance between slits
= Wavelength
Replacing with our values we have,


Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then



Thus the width of the central maximum is


Therefore the widht is 0.466m
<span>It would be hotter near the Earth's equator and colder near Earth's poles</span>