1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhenek [66]
3 years ago
5

Help please ! ASAP !

Chemistry
1 answer:
babymother [125]3 years ago
5 0
Question 24 is 56 because the nuetrons don't have weight
You might be interested in
flammability is a material s ability to burn in the presence of a. hydrogen. b. nitrogen. c. oxygen. d. carbon dioxide.
WARRIOR [948]
I'm guessing it's C-Oxygen because in order to burn something, or create fire, oxygen HAS to be present.
4 0
3 years ago
Calculate the molar mass of each of the following:
Allushta [10]

Explanation:

Molar mass

The mass present in one mole of a specific species .

The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .

(a) S₈

Molar mass of of the atoms are -

sulfur, S = 32 g/mol.

Molar mass of  S₈ = 8 * 32 g/mol.  = 256 g/mol.

(b) C₂H₁₂

Molar mass of of the atoms are -

Hydrogen , H = 1 g/mol

Carbon , C = 12 g/mol

Molar mass of C₂H₁₂ = ( 2 * 12 ) + (12 * 1 ) = 36 g /mol

(c) Sc₂(SO₄)₃

Molar mass of of the atoms are -

sulfur, S = 32 g/mol.

oxygen , O = 16 g/mol.

scandium , Sc = 45 g/mol.

Molar mass of Sc₂(SO₄)₃ = (2 * 45 ) + ( 3 *32 ) + ( 12 * 16 ) = 378 g /mol  

(d) CH₃COCH₃ (acetone)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol

oxygen , O = 16 g/mol.

Hydrogen , H = 1 g/mol

Molar mass of CH₃COCH₃ (acetone) = (3 * 12 ) + ( 1 * 16 ) + ( 6 * 1 ) = 58g/mol

(e) C₆H₁₂O₆ (glucose)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol

oxygen , O = 16 g/mol.

Hydrogen , H = 1 g/mol

Molar mass of C₆H₁₂O₆ (glucose) = ( 6 * 12 ) + ( 12 * 1 ) + ( 6 * 16 ) = 108g/mol.

6 0
3 years ago
How can atoms have more than 32 electons?
guajiro [1.7K]
86 atoms have more electrons than Germanium
3 0
3 years ago
In composting, gardeners allow a pile of plant material such as dead leaves to decay. Composting is a form of combustion.
maks197457 [2]

Answer:

This is true

Explanation:

Because it mixes in with the earth making the earth more suitable for gardening and/or farming.

8 0
3 years ago
A 32.4 L gas sample at STP is compressed to a volume of 28.4 L, and the temperature is increased to 352 K. What is the new press
Sindrei [870]

Answer:

1.47 atm

Explanation:

Step 1: Given data

  • Initial volume (V₁): 32.4 L
  • Initial pressure (P₁): 1 atm (standard pressure)
  • Initial temperature (T₁): 273 K (standard temperature)
  • Final volume (V₂): 28.4 L
  • Final pressure (P₂): ?
  • Final temperature (T₂): 352 K

Step 2: Calculate the final pressure of the gas

We can calculate the final pressure of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

P₂ = P₁ × V₁ × T₂ / T₁ × V₂

P₂ = 1 atm × 32.4 L × 352 K / 273 K × 28.4 L = 1.47 atm

7 0
3 years ago
Other questions:
  • Express 578,000 in scientific notation
    10·1 answer
  • The students teacher explained that vinegar, which is an acid (liquid), and the baking soda, which is a base (solid), reacted an
    13·1 answer
  • Reactants → products
    9·1 answer
  • POINTS!!!!
    10·1 answer
  • CALCULATE: you need to type/show your work. There is no credit if the work is not show/typed Titanium has five common isotopes:
    7·1 answer
  • Magma can partially crystallize at depth and then rise to shallow depths where the remaining magma solidifies. The early-formed
    12·1 answer
  • Que. 1. Gallium has 2 naturally occuring Isotopes with mass numbers 69 & 71 respectively. What is the percentage abundance o
    12·1 answer
  • Who knows Cameron Herrin?​
    10·1 answer
  • 7 grams of oxygen gas is reacted with excess C4H8. How many grams of CO2 gas at STP are produced?
    6·1 answer
  • What is the purpose of the scientific method?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!