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Temka [501]
3 years ago
7

A chemical reaction gives off 2,100 kJ of heat energy. About how many calories is this ?

Chemistry
2 answers:
Inessa05 [86]3 years ago
6 0

Answer: 501900 calories.

Explanation:

Exothermic processes are those processes in which heat is released and endothermic processes are those processes in which heat is absorbed.

Standard units for heat measurement are Joules and calories wherein  

1 joule = 0.239 Calorie.

Now 1 kJ = 1000 Joules

Therefore 2100kJ = 2100\times1000=2100000Joules

As 1 Jolule is equivalent to 0.239 calorie

2100000 Joules are equivalent to=\frac{0.239}{1}\times 2100000= 501900calories

Thus it is 501900 calories.

n200080 [17]3 years ago
3 0

We have to convert 2100 kilojoule into calories.

2100 Kilojoule is equal to 500 Calories.

The chemical reaction gives off 2100 Kilojoule of heat energy which indicates that the reaction is exothermic in nature. Calorie and Kilojoule both are units of energy. We know, 1 calorie=4.2 kilojoule= 4.2 KJ. So 4.2 KJ is equal to 1 Calorie i.e, 4.2 KJ= 1 Calorie. So, to convert KJ to calorie, we have to divide the energy given in KJ by quantity 4.2. Hence, 2100 Kilojoule energy is equal to \frac{1 X 2100}{4.2} Calorie= 500 Calories.



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There are two terms

a) accuracy : it relates to the exactness of an answer that how an answer is close to the actual answer or actual reading

So 104.6 is accurate

b) Precision : This is related to the closeness of different readings with each other

The first reading is 103.7 and the second one is 108.4  so the second reading is quite different from the first reading so it cannot be called as precised

Again 105.8 has good difference from the second reading hence again this is not precised

However the last reading 104.6 is quite near to 105.8 so 104.6 can be called as precise


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When balancing redox reactions under basic conditions in aqueous solution, the first step is to:________.
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Answer:

When balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.

Explanation:

Oxidation-reduction reactions or redox reactions are those in which an electron transfer occurs between the reagents. An electron transfer implies that there is a change in the number of oxidation between the reagents and the products.

The gain of electrons is called reduction and the loss of electrons oxidation. That is to say, there is oxidation whenever an atom or group of atoms loses electrons (or increases its positive charges) and in the reduction an atom or group of atoms gains electrons, increasing its negative charges or decreasing the positive ones.

The oxidation and reduction half-reactions, in a basic medium, adjust the oxygens and hydrogens as follows:

In the member of the half-reaction that presents excess oxygen, you add as many water molecules as there are too many oxygen. Then, in the opposite member, the necessary hydroxyl ions are added to fully adjust the half-reaction. Normally, twice as many hydroxyl ions, OH-, are required as water molecules have previously been added.

In short, you first adjust the oxygens with OH-, then you adjust the H with H₂O, and finally you adjust the charge with e-

So, <u><em>when balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.</em></u>

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