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nata0808 [166]
3 years ago
5

Why must living things rely on thousands of catalysts for chemical reactions necessary for life?

Chemistry
2 answers:
just olya [345]3 years ago
8 0
<span>It affects only one chemical reaction</span>
Ulleksa [173]3 years ago
5 0
It effect only chemical reaction
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Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:
Andru [333]

Answer:

gde

Explanation:

We are attempting to synthesize 1-butyne from 1-chlorobutane. Since 1-chlorobutane is a primary alkyl halide, 1-butene is formed when 1-chlorobutane is reacted with a bulky base such as t -BuOK or t -BuOH in presence of strong heat. This is an E2 reaction.

Secondly, the 1-butene is reacted with bromine in carbon tetrachloride. The vicinal dihalide (1,2-dibromobutane) is formed. This can now undergo further elimination reactions in the presence of sodamide and strong heat to yield 1-butyne which is the desired product. These reactions involve the elimination of the first HBr molecule to give an alkenyl bromide. A second elimination now gives the terminal alkyne.

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3 years ago
What is the starting molecule for glycolysis?
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Glucose is the starting molecule for glycolysis.
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3 years ago
What is the mass of 1.25 mol of zinc ​
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Answer:

1 mole is equal to 1 moles Zinc, or 65.38 grams.

Explanation:

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5 0
3 years ago
Problem Page Predict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure t
Helga [31]

Answer:

CaCl2 + H2O  Ca2+(aq) + 2Cl-(aq)

Explanation:

CaCl2 + H2O  Ca2+(aq) + 2Cl-(aq)

When CaCl2 is dissolved in H2O (water) it will dissociate (dissolve) into Ca+2 and Cl- ions.

The dissolution of calcium chloride is an exothermic process.  

6 0
3 years ago
15.0 g of cream at 10.0 ℃ are added to an insulated cup containing 150.0 g of coffee at 78.6 °C. Calculate the equilibrium tempe
elena-14-01-66 [18.8K]

Answer:

The equilibrium temperature of the coffee is 72.4 °C

Explanation:

Step 1: Data given

Mass of cream = 15.0 grams

Temperature of the cream = 10.0°C

Mass of the coffee = 150.0 grams

Temperature of the coffee = 78.6 °C

C = respective specific heat of the substances( same as water) = 4.184 J/g°C

Step 2: Calculate the equilibrium temperature

m(cream)*C*(T2-T1) = -m(coffee)*c*(T2-T1)

15.0 g* 4.184 J/g°C *(T2 - 10.0°C) = -150.0g *4.184 J/g°C*(T2-78.6°C)

62.76T2 - 627.6 = -627.6T2 + 49329.36

690.36T2 = 49956.96

T2 = 72.4 °C

The equilibrium temperature of the coffee is 72.4 °C

7 0
3 years ago
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