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nata0808 [166]
2 years ago
5

Why must living things rely on thousands of catalysts for chemical reactions necessary for life?

Chemistry
2 answers:
just olya [345]2 years ago
8 0
<span>It affects only one chemical reaction</span>
Ulleksa [173]2 years ago
5 0
It effect only chemical reaction
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Figure 4, Future climate prediction for North America. By 2100, the low-emissions scenario (550 ppm CO2, left) and high-emission
ella [17]

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Las Vegas is expected to recieve less precipitation

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Convert 29.85 degree Celsius to Kelvin
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3 years ago
Is it likely that an atom of Te would substitute for an atom of O in a solid compound? yes no indeterminate
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The correct answer is no.

Explanation:

Tellurium is a chemical element denoted by Te and having atomic number 52. It is mildly toxic, brittle, silver-white, and rare metalloid. The element is chemically related to sulfur and selenium, all three of which are chalcogens.  

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3 years ago
Identify the substance that conducts electricity. question 19 options: 1) nacl dissolved in water 2) solid nacl 3) solid sugar 4
Delicious77 [7]

The substance that conducts electricity is NaCl dissolved in water.

So, option A is correct one.

When the sodium chloride dissolve in water , the sodium atoms and chlorine atoms separates under the presence of water molecules and exist as sodium cation and chloride anion . Now , they are free to move around in the water as positively and negatively charged ions . This separation of charge allows the solution to conduct electricity.

The solid NaCl and solid sugar does not conduct electricity because it is not dissolve in water . Similarly, sugar dissolved in water does not conduct electricity .

to learn more about conduct electricity.

brainly.com/question/1458220

#SPJ4

4 0
1 year ago
A certain radioactive nuclide has a half life of 1.00 hour(s). Calculate the rate constant for this nuclide. s-1 Calculate the d
Karo-lina-s [1.5K]

Answer:

k= 1.925×10^-4 s^-1

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Explanation:

From the information provided;

t1/2=Half life= 1.00 hour or 3600 seconds

Then;

t1/2= 0.693/k

Where k= rate constant

k= 0.693/t1/2 = 0.693/3600

k= 1.925×10^-4 s^-1

Since 1 mole of the nuclide contains 6.02×10^23 atoms

Rate of decay= rate constant × number of atoms

Rate of decay = 1.925×10^-4 s^-1 ×6.02×10^23 atoms

Rate of decay= 1.2 ×10^20 atoms/s

8 0
2 years ago
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