Sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
As given,
Let a-d, a, a +d be three numbers
Sum =33
⇒a-d + a +a +d =33
⇒ a =11
Sum of cubes= 5049
⇒ (a-d)³ + a +(a +d)³ =5049
⇒ a³ -d³ -3a²d +3ad² + a³ +a³ +d³ +3a²d +3ad² =5049
⇒3a³ + 6ad² = 5049
⇒ d=± 4
Therefore, sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
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Answer:
G. (8,6)
Step-by-step explanation:
remember that EF is four times the length of DE
so the distance between E and D multiplied by 4 should equal F
The answer is 50/27 or 1 23/27 or approx 1.85185. Here is my work!
Multiply both sides by 10 : 20x + 6x = 50 - x
Collect the like terms: 20x + 6x = 50 - x
Move Variable to Left: 26x + x = 50
Collect like terms: 27x = 50
Divide both sides by 27: 50/27
Hope this helped :))
Let the perimeter be x.
3x = 75 - 2x
Add 2x from both sides:
5x = 75
Divide both sides by 5:
x = 15
Answer: The perimeter is 15 units.
