What is the domain of the relation?

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

4 0

Answer:

(03.01) The domain of a relation is the output (y) values of the relation the input (x) values of the relation a set of points that pair input values with output values x and y values written in the form (x, y)

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V²=u²+2as make u as the subject

yKpoI14uk [10]

Answer:

u as the subject of the given formula is, $u = \sqrt{v^{2}-2as }$

Step-by-step explanation:

Given;

v² = u²+2as

To make u the subject of the formula, the following steps are taken;

v² = u²+2as

v² - 2as = u²

take the square - root of both sides of the equation;

$\sqrt{u^{2} } = \sqrt{v^{2}-2as } \\\\u = \sqrt{v^{2}-2as }$

Thus, u as the subject of the given formula is, $u = \sqrt{v^{2}-2as }$

5 0

3 years ago

Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

Lostsunrise [7]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$