Convert 459 L into milliliters

Your friend has decided to make some money during the next State Fair by inventing a game of skill. In the game as she has devel

coldgirl [10]

Answer: from the vertical, one should aim 86.6°

Explanation:

height of the center of object = 7.0 m - 0.05 m = 6.95 m

now let the bullet hits centre at point A height x meters from the ground

also let t be the time taken for the bullet to hit the object

so distance travelled by the target will be

d = h - x = 6.95 - x

now using the equation of motion

d = 1/2gt²

so 1/2gt² = 6.95 - x

x = 6.95 - 1/2gt² .........let this be equ 1

let angle of fire be ∅

so v(cos∅) × t = 100

our velocity v is 1200 ft/sec = 365.76 m/s

365.76(cos∅) × t = 100 ........equ 2

also vertical position of the bullet after t is

y = y₀ + c(sin∅)t - 1/2gt²

y = 1 + 365.76(sin∅)t - 1/2gt² ----- equ 3

After time t. the vertical position x and y are same, else the bullet wouldn't have strike target at centre, so;

x = y

we substitute

equ 1 = equ 3

6.95 - 1/2gt² = 1 + 365.76(sin∅)t - 1/2gt²

6.95 - 1 = 365.76(sin∅)t - 1/2gt² + 1/2gt²

5.95 = 365.76(sin∅)t

t = 5.96 / 365.76(sin∅)

now input the above equ into equ 2

365.76(cos∅) × 5.96/365.76(sin∅) = 100

5.95(cos∅)/sin∅ = 100

tan∅ = 5.95/100 = 0.0595

∅ = 3.40°

therefore from the vertical, one should aim (90° - 3.40°) = 86.6°

4 0

4 years ago

I need to find 1).a,b,c

Aleksandr [31]

Let's cut through the weeds and the trash
and get down to the real situation:

A stone is tossed straight up at 5.89 m/s .
      Ignore air resistance.

Gravity slows down the speed of any rising object by 9.8 m/s every second.
So the stone (aka Billy-Bob-Joe) continues to rise for

   (5.89 m/s / 9.8 m/s²) = 0.6 seconds.

At that timer, he has run out of upward gas. He is at the top
of his rise, he stops rising, and begins to fall.

His average speed on the way up is (1/2) (5.89 + 0) = 2.945 m/s .

Moving for 0.6 seconds at an average speed of 2.945 m/s,
he topped out at

(2.945 m/s) (0.6 s) = 1.767 meters above the trampoline.

With no other forces other than gravity acting on him, it takes him
the same time to come down from the peak as it took to rise to it.

   (0.6 sec up) + (0.6 sec down) = 1.2 seconds until he hits rubber again.

5 0

4 years ago

A child is swinging back and forth with a constant period and amplitude. Somewhere in front of the child, a stationary horn is e

Amanda [17]

Answer:

Explanation:

We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .

f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .

f will be lowest when v₀ is highest .

velocity of observer is highest when he is at the equilibrium position or at middle point .

So apparent frequency is lowest when observer is at the middle point and going away from the source while swinging to and from before the source of sound .

3 0

3 years ago

Why is it dangerous to connect a battery to itself. what is the term used to describe that

Yuki888 [10]

In the circuit outside of the battery the electrons have to expend all of their energy on the internal resistance of the battery which causes heating

8 0

3 years ago

Which one of the following temperatures is equal to 5°C?

natali 33 [55]

Answer : The correct option is, (D) 278 K

Explanation :

We are given temperature $5^oC$ .