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Serjik [45]
2 years ago
8

Oceans and other bodies of water are found on which layer of earth

Physics
1 answer:
satela [25.4K]2 years ago
7 0

Answer:

They are found in the Hydrosphere

Explanation:

holped it helped!!

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A 920-kg compact car moving at 92 m/s has approximately 3,893,440 Joules of kinetic energy. What is the change in kinetic energy
tensa zangetsu [6.8K]

Answer:

Change in kinetic energy = 3297280 J

Explanation:

Given that,

Mass, m = 920 kg

Speed of a car, v = 92 m/s

Kinetic energy, K = 3,893,440 J

If the speed of a car, V = 36 m/s

Net kinetic energy is given by :

K_n=\dfrac{1}{2}mV^2\\\\=\dfrac{1}{2}\times 920\times (36)^2\\\\K_n=596160\ J

The change in kinetic energy = 3,893,440 - 596160

= 3297280 J

So, the change in kinetic energy of the car is 3297280 J.

3 0
3 years ago
Which law of motion accounts for the following statement?
strojnjashka [21]
I know that its not the second law. I'm almost positive its the first one. Please let me know if I'm wrong. This sentence makes no sense when you put it with the third law. So, the first law is my guess...
3 0
3 years ago
Read 2 more answers
You fill a 22-cm-tall container with glycerol so that
Ne4ueva [31]

50 POINTS WASTED IMAO

5 0
3 years ago
In order for an external force to do work on a system, Question 9 options: a) there must be a component of the force perpendicul
zepelin [54]

Answer:

b) there must be a component of force parallel to the motion of the object.

Explanation:

We know that work done on a body by an external force is calculated by the formula given below:

W = F.d = Fd Cos θ

where,

W = Work Done by the force on the body

F = Magnitude of force

d = displacement of the body

θ = The angle between the direction of motion of the body and the force applied

It is clear from the formula of the work done, that "F Cosθ" represents the component of the force, that is acting in the direction of motion of the object or parallel to the direction of motion of the object. So, if there is no component of force parallel to motion of object, then this factor will become zero. As a result, the work done will also be zero.

Therefore, the correct option will be:

b) <u>there must be a component of force parallel to the motion of object.</u>

6 0
3 years ago
What is the magnitude of the electric force on an electron in a uniform electric field of strength 2050 n/c that points due east
erastova [34]
Given E=2050 N/C

charge of an electron = 1.6×10^-19 C

USING E = F/Q , electric field = force ÷ charge

2050 = F ÷ (1.6×10^-19)....

make F subject of formula and get the answer 
3 0
3 years ago
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