Answer:
its keeps the fur straight.....im kinda confused with the question
Explanation:
Answer:
t = 4.0 min
Explanation:
given data:
diameter of rod = 2 cm
T_1 = 100 degree celcius
Air stream temperature = 20 degree celcius
heat transfer coefficient = 200 W/m2. K
WE KNOW THAT
copper thermal conductivity = k = 401 W/m °C
copper specific heat Cp = 385 J/kg.°C
density of copper = 8933 kg/m3
charateristic length is given as Lc
Biot number is given as 
Bi = 0.0025
As Bi is greater than 0.1 therefore lumped system analysis is applicable
so we have
............1
where b is given as
b = 0.01163 s^{-1}
putting value in equation 1
solving for t we get
t = 4.0 min
Answer:
Acceleration= 1,59 (meters/(second^2))
Direction= NE; 65,22° above the east direction.
Explanation:
Resulting force= ( ((180N)^2) + ((390N)^2) ) ^ (1/2) = 429,53 N
Angle obove the east direction= ((cos) ^ (-1)) (180N / 429,53 N) = 65,22°
Acceleration= Resulting force / mass = (429,53 N) / (270 kg) =
= (429,53 kg × (meters/(second^2))) / (270kg) = 1,59 (meters/(second^2))
Answer:
the one that is clicked in the photo I think is right
Answer:
34.8 and 55.2º
Explanation:
This is a projectile launching exercise, as we are told that the range of the arrow must be equal to its range and = 31 m let's use the equation
The scope equation is
R = v₀² sin 2θ /g
sin 2 θ = R g / v₀²
sin 2 θ = 31 9.8 / 18²
2 θ = sin⁻¹ 0.93765
θ = 34.8º
At the launch of projectiles we have two complementary angles with the same range in this case 34.8 and (90-34.8) = 55.2º
