Answer:
increase
Explanation:
According to Einstein's photoelectric equation; the energy of a photon striking a metal surface is related to the kinetic energy of the ejected photoelectron by the formula;
KE= hf - hfo
Where h is the planks constant, f and fo refer to the frequency of incident photon and the threshold frequency respectively.
Hence, we can clearly see from the foregoing that the kinetic energy of the ejected photoelectron is proportional to the frequency of the incident photon.
Hence, if the frequency of the incident photon is increased, the kinetic energy of the ejected photoelectron increases also.
The answer is C, 50J
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Answer:
B) T > ma.
Explanation:
To solve this problem, we have to analyze the forces acting in the horizontal direction.
In the horizontal direction, we have:
- The horizontal component of the tension in the wire,
, where T is the magnitude of the tension and
the angle that the wire makes with the horizontal
Since this is the only force acting on the box in the horizontal direction, this is also the net force, so it is equal to the product of mass and acceleration (Newton's second law of motion):
![Tcos \theta = ma](https://tex.z-dn.net/?f=Tcos%20%5Ctheta%20%3D%20ma)
where
m is the mass of the box
a is the acceleration
We can rewrite the equation as
![T=\frac{ma}{cos \theta}](https://tex.z-dn.net/?f=T%3D%5Cfrac%7Bma%7D%7Bcos%20%5Ctheta%7D)
The angle in this problem is
, so
![T=\frac{ma}{cos 15^{\circ}}=\frac{ma}{0.966}=1.035 ma](https://tex.z-dn.net/?f=T%3D%5Cfrac%7Bma%7D%7Bcos%2015%5E%7B%5Ccirc%7D%7D%3D%5Cfrac%7Bma%7D%7B0.966%7D%3D1.035%20ma)
Therefore, the correct option is
B) T > ma.