Proton
charge +
electron
charge -
neutron
charge neutral
<span>This statement simply implies that the 50 million tons of coal will produce the same energy output in one year as the 0.6 million barrels per day of oil. Assuming coal is more plentiful than oil, this is significant as 50 million tons is much smaller than 219 million barrels of oil.</span>
Answer:
The capital of Prince Edward Island is Charlottetown.
Explanation:
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Answer:
The induced current and the power dissipated through the resistor are 0.5 mA and
.
Explanation:
Given that,
Distance = 1.0 m
Resistance = 3.0 Ω
Speed = 35 m/s
Angle = 53°
Magnetic field 
(a). We need to calculate the induced emf
Using formula of emf

Where, B = magnetic field
l = length
v = velocity
Put the value into the formula


We need to calculate the induced current


Put the value into the formula


(b). We need to calculate the power dissipated through the resistor
Using formula of power

Put the value into the formula


Hence, The induced current and the power dissipated through the resistor are 0.5 mA and
.